检查子字符串存在于C中的字符串中

Question

我正在尝试检查字符串是否包含C中的子字符串,如:

char *sent = "this is my sample example";
char *word = "sample";
if (/* sentence contains word */) {
    /* .. */
}

什么是使用而不是string::find在C++中？

Answer 1

if(strstr(sent, word) != NULL) {
    /* ... */
}

请注意,如果找到strstr单词,sent则返回指向单词开头的指针word.

Answer 2

使用strstr此.

http://www.cplusplus.com/reference/clibrary/cstring/strstr/

所以,你会写它...

char *sent = "this is my sample example";
char *word = "sample";

char *pch = strstr(sent, word);

if(pch)
{
    ...
}

Answer 3

尝试使用指针......

#include <stdio.h>
#include <string.h>

int main()
{

  char str[] = "String1 subString1 Strinstrnd subStr ing1subString";
  char sub[] = "subString";

  char *p1, *p2, *p3;
  int i=0,j=0,flag=0;

  p1 = str;
  p2 = sub;

  for(i = 0; i<strlen(str); i++)
  {
    if(*p1 == *p2)
      {
          p3 = p1;
          for(j = 0;j<strlen(sub);j++)
          {
            if(*p3 == *p2)
            {
              p3++;p2++;
            } 
            else
              break;
          }
          p2 = sub;
          if(j == strlen(sub))
          {
             flag = 1;
            printf("\nSubstring found at index : %d\n",i);
          }
      }
    p1++; 
  }
  if(flag==0)
  {
       printf("Substring NOT found");
  }
return (0);
}

Answer 4

您可以尝试使用此方法查找子字符串的存在并提取并打印它：

#include <stdio.h>
#include <string.h>

int main(void)
{
    char mainstring[]="The quick brown fox jumps over the lazy dog";
    char substring[20], *ret;
    int i=0;
    puts("enter the sub string to find");
    fgets(substring, sizeof(substring), stdin);
    substring[strlen(substring)-1]='\0';
    ret=strstr(mainstring,substring);
    if(strcmp((ret=strstr(mainstring,substring)),substring))
    {
        printf("substring is present\t");
    }
    printf("and the sub string is:::");

    for(i=0;i<strlen(substring);i++)
    {
            printf("%c",*(ret+i));

    }
    puts("\n");
    return 0;
}

Answer 5

这段代码实现了搜索工作原理的逻辑（一种方式），而无需使用任何现成的函数：

public int findSubString(char[] original, char[] searchString)
{
    int returnCode = 0; //0-not found, -1 -error in imput, 1-found
    int counter = 0;
    int ctr = 0;
    if (original.Length < 1 || (original.Length)<searchString.Length || searchString.Length<1)
    {
        returnCode = -1;
    }

    while (ctr <= (original.Length - searchString.Length) && searchString.Length > 0)
    {
        if ((original[ctr]) == searchString[0])
        {
            counter = 0;
            for (int count = ctr; count < (ctr + searchString.Length); count++)
            {
                if (original[count] == searchString[counter])
                {
                    counter++;
                }
                else
                {
                    counter = 0;
                    break;
                }
            }
            if (counter == (searchString.Length))
            {
                returnCode = 1;
            }
        }
        ctr++;
    }
    return returnCode;
}