使用显式类型转换将十六进制整数转换为字符？

Question

我编写了以下代码,但o/p不是预期的？有人指导我吗？

问题:编写一个示例程序来声明一个十六进制整数,并使用显式类型转换将其转换为一个字符？

class hexa
{
public static void main(String ar[])
{
    int hex=0xA;
    System.out.println(((char)hex));
}
}

请告诉我:为什么输出有差异

/*code 1*/
int hex = (char)0xA; 
System.out.println(hex); 
/*code 2*/
int hex = 0xA; 
System.out.println((char)hex);

Answer 1

int hex = 0xA; 
System.out.println( (char)hex );

十六进制值0xA(或十进制10)是ASCII中的"\n"(新换行符).
因此输出.

编辑(感谢halex在评论中提供更正:

int hex = (char) 0xA;
System.out.println(hex); //here value of hex is '10', type of hex is 'int', the overloaded println(int x) is invoked.

int hex = 0xA;
System.out.println((char) hex); //this is equivalent to System.out.println( '\n' ); since the int is cast to a char, which produces '\n', the overloaded println(char x) is invoked.