我有一张Excel表格,其中我有近150列.我正在编写一个实用程序,在其中将获取列名称为X的列.在另一个线程中,我看到了如何读取XL工作簿和工作表..已编写以下代码..
HSSFSheet sheet = workbook.getSheetAt(0);
Iterator rows = sheet.rowIterator();
while (rows.hasNext())
{
HSSFRow row = (HSSFRow) rows.next();
Iterator cells = row.cellIterator();
List data = new ArrayList();
while (cells.hasNext())
{
HSSFCell cell = (HSSFCell) cells.next();
data.add(cell);
}
sheetData.add(data);
}
}
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那么如何在给出列名的情况下从XL表中获取精确列?
Apache POI API HSSFSheet是基于行的,您需要通过itteration提取列数据,链接下面的链接可能会回答您的问题:
修改代码以搜索第一个工作表的第1行中的字符串
package projectTest.test;
import java.io.FileInputStream;
import java.util.ArrayList;
import java.util.List;
import org.apache.poi.hssf.usermodel.HSSFSheet;
import org.apache.poi.hssf.usermodel.HSSFWorkbook;
import org.apache.poi.poifs.filesystem.POIFSFileSystem;
import org.apache.poi.ss.usermodel.Cell;
import org.apache.poi.ss.usermodel.Row;
public class Poi {
public static void main(String[] args) throws Exception {
//test file is located in your project path
FileInputStream fileIn = new FileInputStream("test.xls");
//read file
POIFSFileSystem fs = new POIFSFileSystem(fileIn);
HSSFWorkbook filename = new HSSFWorkbook(fs);
//open sheet 0 which is first sheet of your worksheet
HSSFSheet sheet = filename.getSheetAt(0);
//we will search for column index containing string "Your Column Name" in the row 0 (which is first row of a worksheet
String columnWanted = "Your Column Name";
Integer columnNo = null;
//output all not null values to the list
List<Cell> cells = new ArrayList<Cell>();
Row firstRow = sheet.getRow(0);
for(Cell cell:firstRow){
if (cell.getStringCellValue().equals(columnWanted)){
columnNo = cell.getColumnIndex();
}
}
if (columnNo != null){
for (Row row : sheet) {
Cell c = row.getCell(columnNo);
if (c == null || c.getCellType() == Cell.CELL_TYPE_BLANK) {
// Nothing in the cell in this row, skip it
} else {
cells.add(c);
}
}
}else{
System.out.println("could not find column " + columnWanted + " in first row of " + fileIn.toString());
}
}
}
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