K20*_*0GH 0 php mysql codeigniter
我在模型中有以下功能,但它会继续返回:
消息:mysql_fetch_array():提供的参数不是有效的MySQL结果资源
而我为我的生活无法弄清楚为什么.
function getNames() {
$query1 = $this->db->query("SELECT * FROM Device_tbl ORDER BY Manufacturer");
$dev = array();
while($row = mysql_fetch_array($query1))
{
$manu = $row['Manufacturer'];
$mod = $row['Model'];
$dev[] = $manu.' '.$mod;
}
return $dev->result();
}
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有人可以帮忙吗?
CodeIgniter的答案是:
$query1 = $this->db->query("SELECT * FROM table");
foreach($query1->result_array() as $row)
{
$manu = $row['column1'];
$mod = $row['column2'];
echo $manu.' '.$mod;
}
return $query1->result();
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