Jus*_*ney 3 mysql sql variables connection federated
我试图在创建脚本中使用一些变量来进行数据库设置.我不确定如何使用它们.请解释如何正确格式化我的代码.下面是我尝试的代码,以及我得到的错误:
SET @username = 'xxxx'; -- store number goes here
SET @password = 'xxxxxx'; -- store password goes here
CREATE TABLE IF NOT EXISTS `my_table` (
`id` int(11) auto_increment,
`release_date` datetime,
`front_image_file` varchar(255),
PRIMARY KEY (`id`)
) ENGINE=FEDERATED
DEFAULT CHARSET=latin1
AUTO_INCREMENT=1
CONNECTION='mysql://`@username`:`@password`@host_name:3306/database_name/table_tame' ;
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错误
#1432 - Can't create federated table. The data source connection string 'mysql://`@username`:`@password`@host_name:3306/databa' is not in the correct format
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我也试过没有`
尝试EdmundG的解决方案
SET @username = 'xxxx'; -- store number goes here
SET @password = 'xxxxxx'; -- store password goes here
CREATE TABLE IF NOT EXISTS `my_table` (
`id` int(11) auto_increment,
`release_date` datetime,
`front_image_file` varchar(255),
PRIMARY KEY (`id`)
) ENGINE=FEDERATED
DEFAULT CHARSET=latin1
AUTO_INCREMENT=1
CONNECTION='Uid=@username; Pwd=@password; Server=****; Port=3306; Database =****; Table=****;' ;
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没有用,仍然说格式不正确
MySQL不支持将变量插值直接转换为这样的语法.
但是,您可以使用这些变量构建一个字符串,然后准备并将其作为动态SQL执行.
SET @username = 'xxxx'; -- store number goes here
SET @password = 'xxxxxx'; -- store password goes here
SET @sql = CONCAT('CREATE TABLE IF NOT EXISTS `my_table` (',
' `id` int(11) auto_increment,',
' `release_date` datetime,',
' `front_image_file` varchar(255),',
' PRIMARY KEY (`id`)',
') ENGINE=FEDERATED',
' DEFAULT CHARSET=latin1',
' AUTO_INCREMENT=1',
' CONNECTION=''mysql://', @username, ':', @password,
'@host_name:3306/database_name/table_tame');
PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE stmt;
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