ken*_*ner 17 wpf xaml contextmenu button
<Button Name="btnFoo" Content="Foo" >
<Button.ContextMenu Placement="Bottom" PlacementTarget="btnFoo">
<MenuItem Header="Bar" />
</Button.ContextMenu>
</Button>
Run Code Online (Sandbox Code Playgroud)
给我一个运行时错误'UIElement'类型没有公共TypeConverter类
我也试过了
<Button Name="btnFoo" Content="Foo" >
<Button.ContextMenu Placement="Bottom" PlacementTarget="{Binding ElementName=btnFoo}">
<MenuItem Header="Bar" />
</Button.ContextMenu>
</Button>
Run Code Online (Sandbox Code Playgroud)
并将ContextMenu放在屏幕的左上角,而不是按钮
Tar*_*ier 25
您应该在按钮上设置ContextMenuService.Placement附加属性,如ContextMenu.Placement文档中的备注中所述.
<Button Name="btnFoo" Content="Foo" ContextMenuService.Placement="Bottom">
<Button.ContextMenu>
<ContextMenu>
<MenuItem Header="Bar" />
</ContextMenu>
</Button.ContextMenu>
</Button>
Run Code Online (Sandbox Code Playgroud)