fvs*_*vss 9 .net asp.net asp.net-mvc razor asp.net-mvc-3
我想知道如何在Create Action上使用我的ViewModel?我尝试了几个我在论坛中找到的例子,但都没有解决我的问题.我已经绞尽脑汁待了几天,但无法弄清楚出了什么问题.
每当我单击"创建"按钮时,我都会收到以下错误:没有为此对象定义无参数构造函数.
@model MvcMusicStore.ViewModels.AlbumViewModel
@{
ViewBag.Title = "Create";
}
<h2>Create</h2>
<script src="@Url.Content("~/Scripts/jquery.validate.min.js")" type="text/javascript"></script>
<script src="@Url.Content("~/Scripts/jquery.validate.unobtrusive.min.js")" type="text/javascript"></script>
@using (Html.BeginForm()) {
@Html.ValidationSummary(true)
<fieldset>
<legend>Album</legend>
<div class="editor-label">
@Html.LabelFor(model => model.AlbumItem.GenreId, "Genre")
</div>
<div class="editor-field">
@Html.DropDownList("Genres", String.Empty)
@Html.ValidationMessageFor(model => model.AlbumItem.GenreId)
</div>
<div class="editor-label">
@Html.LabelFor(model => model.AlbumItem.ArtistId, "Artist")
</div>
<div class="editor-field">
@Html.DropDownList("Artists", String.Empty)
@Html.ValidationMessageFor(model => model.AlbumItem.ArtistId)
</div>
<div class="editor-label">
@Html.LabelFor(model => model.AlbumItem.Title)
</div>
<div class="editor-field">
@Html.EditorFor(model => model.AlbumItem.Title)
@Html.ValidationMessageFor(model => model.AlbumItem.Title)
</div>
<div class="editor-label">
@Html.LabelFor(model => model.AlbumItem.Price)
</div>
<div class="editor-field">
@Html.EditorFor(model => model.AlbumItem.Price)
@Html.ValidationMessageFor(model => model.AlbumItem.Price)
</div>
<div class="editor-label">
@Html.LabelFor(model => model.AlbumItem.AlbumArtUrl)
</div>
<div class="editor-field">
@Html.EditorFor(model => model.AlbumItem.AlbumArtUrl)
@Html.ValidationMessageFor(model => model.AlbumItem.AlbumArtUrl)
</div>
<p>
<input type="submit" value="Create" />
</p>
</fieldset>
}
<div>
@Html.ActionLink("Back to List", "Index")
</div>
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Create.cshtml
public class StoreManagerController : Controller
{
private MusicStoreDB db = new MusicStoreDB();
//
// GET: /StoreManager/Create
public ActionResult Create()
{
var viewModel = new AlbumViewModel()
{
Genres = new SelectList(db.Genres, "GenreId", "Name"),
Artists = new SelectList(db.Artists, "ArtistId", "Name")
};
return View(viewModel);
}
//
// POST: /StoreManager/Create
[HttpPost]
public ActionResult Create(AlbumViewModel vm)
{
if (ModelState.IsValid)
{
db.Albums.Add(vm.AlbumItem);
db.SaveChanges();
return RedirectToAction("Index");
}
vm.Genres = new SelectList(db.Genres, "GenreId", "Name", vm.AlbumItem.GenreId);
vm.Artists = new SelectList(db.Artists, "ArtistId", "Name", vm.AlbumItem.ArtistId);
return View(vm);
}
}
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StoreManager.cs - 片段
public class AlbumViewModel
{
public AlbumViewModel()
{
// nothing
}
public Album AlbumItem { get; set; }
public SelectList Genres { get; set; }
public SelectList Artists { get; set; }
}
public class Album
{
public Album()
{
// nothing
}
public virtual int AlbumId { get; set; }
public virtual int GenreId { get; set; }
public virtual int ArtistId { get; set; }
public virtual string Title { get; set; }
public virtual decimal Price { get; set; }
public virtual string AlbumArtUrl { get; set; }
public virtual Genre Genre { get; set; }
public virtual Artist Artist { get; set; }
}
public class Artist
{
public Artist()
{
// nothing
}
public virtual int ArtistId { get; set; }
public virtual string Name { get; set; }
}
public class Genre
{
public Genre()
{
// nothing
}
public virtual int GenreId { get; set; }
public virtual string Name { get; set; }
public virtual string Description { get; set; }
public virtual List<Album> Albums { get; set; }
}
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Eri*_*sch 28
如果我每次看到这个问题都有镍.它通常与模型属性的命名以及如何在a中使用它们有关DropDownList
.99.999%的时间是因为人们正在使用Html.DropDownList()
它并将其命名为与它们相同SelectList
.这是你应该使用强类型的一个原因DropDownListFor
.
在这种情况下,你的问题是,你必须SelectList
的named Genres
和Artists
,然后在您的视图您有:
@Html.DropDownList("Genres", String.Empty)
@Html.DropDownList("Artists", String.Empty)
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看,同名.
你应该做的是改变你的模型,使其SelectList
命名GenreList
和ArtistList
.然后,更改视图以使用强类型模型.
@Html.DropDownListFor(m => m.AlbumItem.GenreID, Model.GenreList)
@Html.DropDownListFor(m => m.AlbumItem.ArtistID, Model.ArtistList)
Run Code Online (Sandbox Code Playgroud)
发生这种情况的原因是您将一个名为Genres的值发布到控制器.默认模型绑定器在模型中尽职尽责地查找名为Genres的内容并实例化它.但是,它找到一个名为Genres的SelectList,而不是ID或字符串,当它尝试实例化它时,它发现没有默认构造函数.
因此你的错误.SO充满了询问同样事情的问题.
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