App*_*sei 5 java algorithm arraylist
我的逻辑搞砸了.我只是试图找到一种方法来删除ArrayList中的重复项而不使用HashSet.
public static void main(String[] args) {
ArrayList<String> wordDulicate = new ArrayList<String>();
wordDulicate.add("Tom");
wordDulicate.add("Jones");
wordDulicate.add("Sam");
wordDulicate.add("Jamie");
wordDulicate.add("Robie");
wordDulicate.add("Helen");
wordDulicate.add("Tom");
wordDulicate.add("Troy");
wordDulicate.add("Mika");
wordDulicate.add("Tom");
for (String dupWord : wordDulicate) {
if (wordDulicate.equals(dupWord))
System.out.println(wordDulicate.get(dupWord));
}
}
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您可以创建另一个列表,并向其中添加项目,跳过重复项: -
ArrayList<String> wordDulicate = new ArrayList<String>();
ArrayList<String> tempList= new ArrayList<String>();
wordDulicate.add("Tom");
wordDulicate.add("Jones");
wordDulicate.add("Sam");
for (String dupWord : wordDulicate) {
if (!tempList.contains(dupWord)) {
tempList.add(dupWord);
}
}
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此方法需要另一个列表:
ArrayList<String> wordDulicate = new ArrayList<String>();
wordDulicate.add("Tom");
wordDulicate.add("Jones");
wordDulicate.add("Sam");
wordDulicate.add("Jamie");
wordDulicate.add("Robie");
wordDulicate.add("Helen");
wordDulicate.add("Tom");
wordDulicate.add("Troy");
wordDulicate.add("Mika");
wordDulicate.add("Tom");
ArrayList<String> nonDupList = new ArrayList<String>();
Iterator<String> dupIter = wordDulicate.iterator();
while(dupIter.hasNext())
{
String dupWord = dupIter.next();
if(nonDupList.contains(dupWord))
{
dupIter.remove();
}else
{
nonDupList.add(dupWord);
}
}
System.out.println(nonDupList);
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输出:
[Tom, Jones, Sam, Jamie, Robie, Helen, Troy, Mika]
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