Das*_*123 12 mysql sql join count
我正在尝试使用以下代码获取4个特定部分中的文档计数:
SELECT
category.id
, category.title
, count(ts1.section_id) AS doc1
, count(ts2.section_id) AS doc2
, count(ts3.section_id) AS doc3
, count(ts4.section_id) AS doc4
FROM
category
LEFT JOIN category_link_section AS ts1
ON (category.id = ts1.category_id AND ts1.section_id = 1)
LEFT JOIN category_link_section AS ts2
ON (category.id = ts2.category_id AND ts2.section_id = 2)
LEFT JOIN category_link_section AS ts3
ON (category.id = ts3.category_id AND ts3.section_id = 3)
LEFT JOIN category_link_section AS ts4
ON (category.id = ts4.category_id AND ts4.section_id = 4)
GROUP BY category.id, ts1.section_id, ts2.section_id, ts3.section_id, ts4.section_id
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表'category'具有id,title等.表'category_link_section'包含category_id,section_id和doc_id之间的id链接.
如果任何列的计数为0,则该列中显示0.但如果结果不为0,则显示所有截面结果的乘法结果.所以,如果我的4个计数列应该返回:1,2,3,3; 它实际上会显示6,6,0,6;
如果我对每个特定类别使用以下代码,我会得到我想要的结果:
SELECT
category.id
, category.title
, count(ts1.section_id) AS doc1
FROM
category
LEFT JOIN category_link_section AS ts1
ON (category.id = ts1.category_id AND ts1.section_id = 1)
GROUP BY category.id, ts1.section_id
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但是我需要每次为每个部分循环访问数据库.
所以我的问题是,我是否需要逐步调用每个部分,在SQL之外构建我的表,还是可以在一个查询中完成?
Bil*_*win 26
@ VoteyDisciple的回答是正确的,但他的查询需要一些改进:
SELECT c.id, c.title,
SUM(ts1.section_id = 1) AS doc1,
SUM(ts1.section_id = 2) AS doc2,
SUM(ts1.section_id = 3) AS doc3,
SUM(ts1.section_id = 4) AS doc4
FROM category AS c
LEFT JOIN category_link_section AS ts1
ON (c.id = ts1.category_id)
GROUP BY c.id;
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说明:
IF()
表达式是多余的,因为平等已经返回1或0.ts1.section_id=1
出在连接条件的,否则你将永远不会得到其他section_id
值.c.id
仅限分组.我假设OP每个类别只需要一行,并且section_id
相应类别的每个值的计数列.如果查询按分组c.id, ts1.section_id
排列,则每个类别最多有四行.您可能想尝试这样的事情:
SELECT
category.id
, category.title
, SUM(IF(ts1.section_id = 1, 1, 0)) AS doc1
, SUM(IF(ts1.section_id = 2, 1, 0)) AS doc2
, SUM(IF(ts1.section_id = 3, 1, 0)) AS doc3
, SUM(IF(ts1.section_id = 4, 1, 0)) AS doc4
FROM
category
LEFT JOIN category_link_section AS ts1
ON (category.id = ts1.category_id AND ts1.section_id = 1)
GROUP BY category.id, ts1.section_id
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