使用jQuery调用Spring REST WebService

Pau*_*aul 1 rest jquery spring web-services put

我想用JQuery调用Spring REST WebService.

我的控制器中有两种方法:

@RequestMapping(value="/{id}", method=RequestMethod.GET)
public @ResponseBody User getUser(@PathVariable long id, Model model){
return new User("TestUser");
}

@RequestMapping(value="/{id}", method=RequestMethod.PUT)
@ResponseStatus(HttpStatus.NO_CONTENT)
public void updateUser(@PathVariable long id, @Valid User user){
    user.getName();
}
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User类看起来像这样:

public class User {

private String name;

public User(){};
public User(String name){this.name = name;}

public String getName() {
    return name;
}
public void setName(String name) {
    this.name = name;
};
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}

现在,当我调用http://localhost:8080/demo/user/2结果时,{"name":"TestUser"}就像预期的那样.

但是在尝试修改资源时,我尝试这样做:

$.ajax({
  url: "http://localhost:8080/demo/user/2",
  dataType: "json",
  data: '{"name":"NewTestUser"}',
  type: "PUT",
  success: function(){alert('success');}
});
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我可以在Debugmode中看到调用了正确的方法(updateUser),但User对象的实例变量名始终为null.谁能告诉我我做错了什么?谢谢!

Bij*_*men 5

您还必须使用注释User参数@RequestBody,这将触发使用Spring MVC注册的httpmessageconverters将http主体转换为您的User类型,这样:

@RequestMapping(value="/{id}", method=RequestMethod.PUT)
@ResponseStatus(HttpStatus.NO_CONTENT)
public void updateUser(@PathVariable long id, @RequestBody @Valid User user){
    user.getName();
}
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