SQL Server - 为xml列返回xml子节点

Pau*_*ing 8 xml sql sql-server sqlxml

给定表T列:

ID UNIQUEIDENTIFIER
CreatedDate DATETIME
XmlData XML
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XmlData的结构如下:

<application>
    <details firstname="first" lastname="last">
        <statement>statement</statement>
    </details>
    <educationHistory>
        <education subject="subject1" />
        <education subject="subject2" />
    </educationHistory>
    <experienceHistory>
        <examiningExperienceHistory>
            <examiningExperience module="module1" />
            <examiningExperience module="module2" />
        </examiningExperienceHistory>
        <teachingExperienceHistory>
            <teachingExperience module="module1" />
            <teachingExperience module="module2" />
        </teachingExperienceHistory>
    </experienceHistory>
</application>
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我需要像这样返回一个提取物:

ID Date       FirstName LastName Education    ExaminingExp TeachingExp
-----------------------------------------------------------------------
1  02-10-2012 First     Last     <xmlextract> <xmlextract> <xmlextract>
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到目前为止,我有:

SELECT ID,
       CreatedDate [Date],
       XmlData.value('(application/details/@firstname)[1]','varchar(max)') [FirstName],
       XmlData.value('(application/details/@lastname)[1]','varchar(max)') [LastName]
FROM T
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我在最后三列中苦苦挣扎.对于每个记录,我需要列出教学/考试经验和教育.有人可以帮忙吗?

pod*_*ska 8

使用.query提取XML.

例如

select 
XmlData.query('/application/educationHistory/*'),
XmlData.query('/application/experienceHistory/examiningExperienceHistory/*'),
XmlData.query('/application/experienceHistory/teachingExperienceHistory/*')
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Jai*_*ime 5

试试这个:

SELECT ID, Created [DATE] 
XmlData.value('(application/details/@firstname)[1]','varchar(max)') [FirstName],
XmlData.value('(application/details/@lastname)[1]','varchar(max)') [LastName],
XmlData.query('/application/educationHistory'),
XmlData.query('/application/experienceHistory/examiningExperienceHistory'),
XmlData.query('/application/experienceHistory/teachingExperienceHistory')
FROM T
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