在jQuery Ajax之后执行功能吗？

Question

我目前正在尝试让我的Ajax将一些信息从HTML表单发布到PHP表单中.

那么,现在我已经制作了差异代码,应该在"ajax.comment.php"页面打印出来,告诉发生了什么.

就像成功与否一样.

我现在想制作我的ajax,检查打印的html是什么.然后处理...就像if(打印HTML =="1"){然后做某事}.

我怎样才能做到这一点？

我的以下javascript是:

var name = document.comment.name.value;
var email = document.comment.email.value;
var website = document.comment.website.value;
var message = document.comment.message.value;
var id = document.comment.id.value;
$.ajax({
      type: "POST",
      url: "ajax.addcomment.php",
      data: "name="+name+"&email="+email+"&website="+website+"&message="+message+"&id="+id,
      beforeSend: function() {
        // Action before sending data
      },
      success: function(returned_html) {
        // Action after sending data, where the returned_html var is the returned html text by the php
      }
  });

Answer 1

在你的success功能中,试试这个:

success: function(returned_html) {
    var the_result = $.trim(returned_html);
    if(the_result == '1')
    {
        // Do whatever you wanted here.
    }
    else
    {
        // Do something else here...
    }
}