iOS 6中不推荐使用的代码回退到iOS 5

Question

我有这个自定义后退按钮:

- (IBAction)backToMenu:(id)sender {

[self.presentingViewController dismissModalViewControllerAnimated:YES]; 

}

在iOS 6模拟器中测试我的应用程序说不推荐使用dismissModalViewControllerAnimated,我必须使用dismissViewControllerAnimated,所以,我如何使用iOS 6代码并回退到iOS 5

我试过这个:

if([self respondsToSelector:@selector(presentingViewController:animated:completion:)])
    [self.presentingViewController dismissViewControllerAnimated:(YES) completion:nil];
else if([self respondsToSelector:@selector(presentingViewController:animated:)])
    [self.presentingViewController dismissModalViewControllerAnimated:YES];
else
    NSLog(@"Oooops, what system is this ?!!! - should never see this !");

但是没有结果,我看到了NSLog并且没有任何视图被解雇,任何提示？

先感谢您.

Answer 1

您正在测试的选择器与您调用的选择器不同.请尝试以下方法:

if([self.presentingViewController respondsToSelector:@selector(dismissViewControllerAnimated:completion:)])
    [self.presentingViewController dismissViewControllerAnimated:(YES) completion:nil];
else if([self.presentingViewController respondsToSelector:@selector(dismissModalViewControllerAnimated:)])
    [self.presentingViewController dismissModalViewControllerAnimated:YES];
else
    NSLog(@"Oooops, what system is this ?!!! - should never see this !");

最重要的区别是,你打电话的对象 - self.presentingViewController在这种情况下-从不同的你是调用对象的方法.我们称后者为选择器,这就是你想要放入@selector()包装器的位.

Answer 2

使用[self dismissViewControllerAnimated:YES completion:Nil]; 对于iOS 6