如何在ScalaTest中显示"should produce [exception]"中抛出的异常

Question

我想显示scala测试中抛出的Exception消息.

 " iWillThrowCustomException Method Failure test.   
 " should "Fail, Reason: Reason for failing. " in {
 evaluating {
      iWillThrowCustomException();
   } should produce [CustomException]
}

如果CustomExeption将为不同的输入抛出不同类型的消息,比如说

(for -ve amount - 金额小于零,金额为chars - 金额无效),

如何显示块中抛出的消息,因为它将通过CustomException它将显示测试成功,但是它为哪个senario抛出了错误

Answer 1

或者你可以看看intercept:

val ex = intercept[CustomException] {
    iWillThrowCustomException()
}
ex.getMessage should equal ("My custom message")

Answer 2

evaluating还会返回一个异常,以便您可以检查它或打印消息.以下是ScalaDoc的示例:

val thrown = evaluating { s.charAt(-1) } should produce [IndexOutOfBoundsException]
thrown.getMessage should equal ("String index out of range: -1")

据我所知,您不能在测试名称中包含异常消息.

您可以做的是添加有关测试的其他信息info():

"iWillThrowCustomException Method Failure test." in {
    val exception = evaluating { iWillThrowCustomException() } should produce [CustomException]
    info("Reason: " + exception.getMessage)
}

这将在测试结果中显示为嵌套消息.您可以在ScalaDoc中找到更多相关信息.