没有实现接口成员 - C#

Question

我不断收到这个错误,我不确定我做错了什么.错误1'Home.Services.InventoryImpl'未实现接口成员'Home.Services.InventorySvc.CreateInventory(Home.Services.InventoryImpl)'

我的接口代码

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using Home;
using Home.Domain;

namespace Home.Services
{
    public interface InventorySvc
    {
        void CreateInventory(InventoryImpl CreateTheInventory);
    }
}

我的实施准则

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using Home.Domain;
using System.IO;
using System.Runtime.Serialization;
using System.Runtime.Serialization.Formatters.Binary;

namespace Home.Services
{
    public class InventoryImpl: InventorySvc
    {
        public void CreateTheInventory(CreateInventory createinventory)
        {

            FileStream fileStream = new FileStream
            ("CreateInventory.bin", FileMode.Create, 
            FileAccess.Write);
            IFormatter formatter = new BinaryFormatter();
            formatter.Serialize(fileStream, createinventory);
            fileStream.Close();
        }
    }
}

Answer 1

调用您的方法,CreateTheInventory但在接口中调用它CreateInventory.方法签名必须与接口成员完全匹配,以便编译器将该方法视为实现接口成员,并且名称不匹配.

此外,参数类型不匹配-在你执行你CreateInventory的参数类型,但接口需要类型的参数InventoryImpl.

如果你纠正了这两个错误,你的代码应该构建.