从某一点来说最近的地方

Question

我有下表

create table places(lat_lng point, place_name varchar(50));

insert into places values (POINT(-126.4, 45.32), 'Food Bar');

什么应该是让所有地方接近特定纬度/经度的查询？

gis已安装.

Answer 1

如果您确实想使用PostGIS:

create table places(
    lat_lng geography(Point,4326),
    place_name varchar(50)
);

-- Two ways to make a geography point
insert into places values (ST_MakePoint(-126.4, 45.32), 'Food Bar1');
insert into places values ('POINT(-126.4 45.32)', 'Food Bar2');

-- Spatial index
create index places_lat_lng_idx on places using gist(lat_lng);

现在找到1公里(或1000米)范围内的所有地方:

select *, ST_Distance(lat_lng, ST_MakePoint(-126.4, 45.32)::geography)
from places
where ST_DWithin(lat_lng, ST_MakePoint(-126.4, 45.32)::geography, 1000)
order by ST_Distance(lat_lng, ST_MakePoint(-126.4, 45.32)::geography);

Answer 2

select *
from places
where lat_lng <-> POINT(-125.4, 46.32) < 1
order by lat_lng <-> POINT(-125.4, 46.32)