返回最后2位数字

Question

我怎样才能得到最后2位数字:

<departureDate>200912</departureDate>

对我的对象:

$year = $flightDates->departureDate->year;

Answer 1

// first two
$year = substr($flightDates->departureDate->year, 0, 2);
// last two
$year = substr($flightDates->departureDate->year, -2);

但鉴于您在这里解析日期这一事实,使用日期函数会更聪明.pe strtotime()和date()甚至:

<?php
$someDate ='200912';
$dateObj = DateTime::createFromFormat('dmy', $someDate);
echo $dateObj->format('Y');
// prints "2012" .. (see date formats)

Answer 2

你可以substr将它作为字符串来解决,函数会自动转换它:

<?php

//$year = '200912';
$year = $flightDates->departureDate->year;

echo substr( $year, -2 );

?>

仔细看看substr函数.如果您希望结果是严格整数,那么只需(int)在返回前添加.

但是,正如Jan.所说,你应该更好地将它作为一个日期:

<?php

//$year = '200912';
$year = $flightDates->departureDate->year;

$date = DateTime::createFromFormat( 'dmy', $year );

echo date( "y", $date->getTimestamp() );

?>