自定义列表排序

Siv*_*iva 3 groovy

嗨,我有一个包含元素[daily,monthly,weekly][monthly,weekly,daily]或的列表[weekly,daily]

我需要以这样的方式对列表进行排序

[daily,monthly,weekly] == [daily,monthly,weekly]

[monthly, weekly, daily] == [daily, monthly, weekly]

[weekly, daily] == [daily, weekly]
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有人可以帮助我

tim*_*tes 5

假设你的意思是你有一个字符串列表,那么这应该工作:

customSorter = { 
  [ 'daily', 'monthly', 'weekly' ].indexOf( it )
}

assert [ 'daily', 'monthly', 'weekly' ].sort( customSorter ) == [ 'daily', 'monthly', 'weekly' ]
assert [ 'monthly', 'weekly', 'daily' ].sort( customSorter ) == [ 'daily', 'monthly', 'weekly' ]
assert [ 'weekly', 'daily' ].sort( customSorter ) == [ 'daily', 'weekly' ]
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或者你可以这样做(避免重复创建一个List)

customSorter = { a, b, order=['daily','monthly','weekly'] ->
  order.indexOf( a ) <=> order.indexOf( b )
}
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