如何使用RESTEasy访问HTTP请求的正文

Question

我正在寻找一种直接访问HTTP请求正文的方法.事实上,在我的代码中,我在身体中接收到不同的参数,我事先并不知道我将收到什么.此外,我希望尽可能灵活:我正在处理可能不同的不同请求,我希望在每种类型的请求(GET,POST,...)的单个方法中处理它们.有没有办法通过RESTEasy处理这种灵活性？我应该切换到别的吗？

Answer 1

根据本答案中给出的代码,您可以访问HTTPServletRequest对象.

一旦有了HTTPServletRequest对象,就应该像往常一样访问请求体.一个例子可以是:

String requestBody = "";
StringBuilder stringBuilder = new StringBuilder();
BufferedReader bufferedReader = null;
try {
    InputStream inputStream = request.getInputStream();
    if (inputStream != null) {
        bufferedReader = new BufferedReader(new InputStreamReader(inputStream));
        char[] charBuffer = new char[128];
        int bytesRead = -1;
        while ((bytesRead = bufferedReader.read(charBuffer)) > 0) {
            stringBuilder.append(charBuffer, 0, bytesRead);
        }
    } else {
        stringBuilder.append("");
    }
} catch (IOException ex) {
    throw ex;
} finally {
    if (bufferedReader != null) {
        try {
            bufferedReader.close();
        } catch (IOException ex) {
            throw ex;
        }
    }
}
requestBody = stringBuilder.toString();