Mik*_*ynn 4 c# asp.net json get query-string
将JSON对象转换为查询字符串以附加到GET Url的最佳方法是什么?POST很简单,我的Web API后端会读取它.
{姓名:'迈克'} =?姓名=迈克
private static string MakeRequest(HttpWebRequest req, string data)
{
try
{
if (req.Method == Verbs.POST.ToString() || req.Method == Verbs.PUT.ToString() || req.Method == Verbs.DELETE.ToString())
{
var encodedData = Encoding.UTF8.GetBytes(data);
req.ContentLength = encodedData.Length;
req.ContentType = "application/json";
req.GetRequestStream().Write(encodedData, 0, encodedData.Length);
}
using (var response = req.GetResponse() as HttpWebResponse)
using (var reader = new StreamReader(response.GetResponseStream()))
{
return reader.ReadToEnd();
}
}
catch (WebException we)
{
if(we.Response == null)
{
return JsonConvert.SerializeObject(new { Errors = new List<ApiError> { new ApiError(11, "API is currently unavailable") }});
}
using (var response = we.Response as HttpWebResponse)
using (var reader = new StreamReader(response.GetResponseStream()))
{
return reader.ReadToEnd();
}
}
}
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L.B*_*L.B 14
如果json对象在您的示例中是平坦的,那么
string json = @"{
""name"": ""charlie"",
""num"": 123
}";
var jObj = (JObject)JsonConvert.DeserializeObject(json);
var query = String.Join("&",
jObj.Children().Cast<JProperty>()
.Select(jp=>jp.Name + "=" + HttpUtility.UrlEncode(jp.Value.ToString())));
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查询将是 name=charlie&num=123
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