Bob*_*yan 1 sorting perl reference
我对Perl比较陌生.我有一个名为$ TransRef的数组的引用,该数组包含对数组的引用.我的目标是编写一个以$ TransRef争论为唯一参数的子,用第二个元素(一个字符串)对底层数组的引用进行排序,并将输出设置回$ TransRef引用.有人可以说明如何在Perl中完成这项工作吗?
以下是一些生成$ TransRef的代码.它还没有经过测试,可能有一些错误:
# Parse the data and move it into the Transactions container.
for ($Loop = 0; $Loop < 5; $Loop++)
{
$Line = $LinesInFile[$Loop];
# Create an array called Fields to hold each field in $Line.
@Fields = split /$Delimitor/, $Line;
$TransID = $Fields[2];
# Save a ref to the fields array in the transaction list.
$FieldsRef = \@Fields;
ValidateData($FieldsRef);
$$TransRef[$Loop] = $FieldsRef;
}
SortByCustID($TransRef);
sub SortByCustID()
{
# This sub sorts the arrays in $TransRef by the 2nd element, which is the cust #.
# How to do this?
my $TransRef = @_;
...
}
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很简单:
sub sort_trans_ref {
my $transRef = shift;
@$transRef = sort { $a->[1] cmp $b->[1] } @$transRef;
return $transRef;
}
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虽然不修改原始数组对我来说更自然:
sub sort_trans_ref {
my $transRef = shift;
my @new_transRef = sort { $a->[1] cmp $b->[1] } @$transRef;
return \@new_transRef;
}
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