将NSNumber(double)值转换为时间

Question

我尝试将像"898.171813964844"这样的值转换为00:17:02(hh:mm:ss).

如何在目标c中完成？

感谢帮助!

Answer 1

最终解决方案

NSNumber *time = [NSNumber numberWithDouble:([online_time doubleValue] - 3600)];
NSTimeInterval interval = [time doubleValue];    
NSDate *online = [NSDate date];
online = [NSDate dateWithTimeIntervalSince1970:interval];    
NSDateFormatter *dateFormatter = [[[NSDateFormatter alloc] init] autorelease];
[dateFormatter setDateFormat:@"HH:mm:ss"];

NSLog(@"result: %@", [dateFormatter stringFromDate:online]);

Answer 2

假设您只对小时,分钟和秒感兴趣并且输入值小于或等于86400,您可以执行以下操作:

NSNumber *theDouble = [NSNumber numberWithDouble:898.171813964844];

int inputSeconds = [theDouble intValue];
int hours =  inputSeconds / 3600;
int minutes = ( inputSeconds - hours * 3600 ) / 60; 
int seconds = inputSeconds - hours * 3600 - minutes * 60; 

NSString *theTime = [NSString stringWithFormat:@"%.2d:%.2d:%.2d", hours, minutes, seconds];