Bla*_*sui 0 excel vba excel-vba mismatch type-mismatch
每次调用此函数都会导致运行时错误"13"类型不匹配.为什么会这样?
Public Function VersionExists(versionId As String)
VersionExists = False
For Each cell In Tabelle2.Columns(1)
If cell.Value = versionId Then
VersionExists = True
End If
Next
End Function
Run Code Online (Sandbox Code Playgroud)
您无法访问cell.value,.Columns(1)因为它返回包含整个列的范围;
For Each cell In Sheet1.Columns(1).Rows '//or .cells
Run Code Online (Sandbox Code Playgroud)
也许在比赛结束后退出for循环也是一个好主意.