您无法使用JSON进行跨域AJAX调用.您需要使用JSONP.因此,不是JsonResult从控制器操作返回常规,而是编写自定义操作结果,将JSON包装在作为参数传递的回调中:
public class JsonpResult : ActionResult
{
private readonly object _obj;
public JsonpResult(object obj)
{
_obj = obj;
}
public override void ExecuteResult(ControllerContext context)
{
var serializer = new JavaScriptSerializer();
var callbackname = context.HttpContext.Request["callback"];
var jsonp = string.Format("{0}({1})", callbackname, serializer.Serialize(_obj));
var response = context.HttpContext.Response;
response.ContentType = "application/json";
response.Write(jsonp);
}
}
Run Code Online (Sandbox Code Playgroud)
然后让控制器操作返回此自定义操作结果:
public ActionResult SomeAction()
{
var result = new[]
{
new { Id = 1, Name = "item 1" },
new { Id = 2, Name = "item 2" },
new { Id = 3, Name = "item 3" },
};
return new JsonpResult(balances);
}
Run Code Online (Sandbox Code Playgroud)
现在您可以跨域使用此操作:
var url = "http://example.com/SomeController/SomeAction/";
$.getJSON(url + '?callback=?', function (data) {
alert(data);
});
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
753 次 |
| 最近记录: |