Sup*_*tar 6 c performance pseudocode greatest-common-divisor ti-basic
我决定实现一个程序,可以在TI-Basic中找到任意两个数字(包括非整数)的GCD.我在Java中使用它很好,所以我知道它有效.它在TI-Basic中运行得很好,但与内置gcd(函数相比,它非常缓慢; 该gcd(函数似乎以毫秒为单位获得结果,其中我的可能需要几秒钟.为什么TI-Basic比预定义的计算器功能慢得多?
以下是TI-Basic中的程序代码,供您检查:
PROGRAM:GCD
:ClrHome
:Disp "Greatest Common"," Divisor"," ---"
:Input "First number? ",X
:Input "Second number? ",Y
:
:X?I
:Y?J
:
:If (I?int(I) or J?int(J))
:Then
:ClrHome
:Disp "Non-integer","inputs may be","innacurate!",""
:End
:If (I=1 or J=1)
:Then
:1?I
:1?J
:Goto Z
:End
:For(C,0,2^8)
:If I=J
:Goto Z
:
:If I>J
:I-J?I
:
:If J>I
:J-I?J
:
:End
:
:Disp "This is a hard","one! Thinking","harder..."
:
:For(C,0,2^15)
:If (I=J)
:Goto Z
:While (I>J)
:I-J?I
:C+1?C
:End
:While (J>I)
:J-I?J
:C+1?C
:End
:End
:
:Disp "TIMED OUT!","Either:",J,"or"
:Pause
:
:Lbl Z
:ClrHome
:Disp "GCD of",X,"and",Y,"is",I
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免责声明:这是我看TI-84并在此输入的结果.可能会有一些拼写错误,尽管我尽力保持不变
对于那些可能不知道这意味着什么的人,下面提供了伪代码:
program gcd()
{
Console.clear();
Console.writeln("Greatest Common");
Console.writeln(" Divisor");
Console.writeln(" ---");
float X = Console.readFloat("First Number? ");
float Y = Console.readFloat("Second number? ");
float I = X;
float J = Y;
if (I != (int)I || J != (int)J)
{
Console.clear();
Console.writeln("Non-integer");
Console.writeln("inputs may be");
Console.writeln("inaccurate!");
Console.writeln("");
}
if (I == 1 or J == 1)
{
I = 1;
J = 1;
goto Z;
}
for(int C = 0, limit = Math.pow(2,8); C < limit; C++)
{
if (I == J)
goto Z;
if (I > J)
I = I - J;
if (J > I)
J = J - I;
}
Console.writeln("This is a hard");
Console.writeln("one! Thinking");
Console.writeln("harder...");
for(int C = 0, limit = Math.pow(2,15); C < limit; C++)
{
if (I == J)
goto z;
while (I > J)
{
I = I - J;
C++;
}
while (J>I)
{
J = J-I;
C++;
}
}
Console.writeln("TIMED OUT!");
Console.writeln("Either:");
Console.writeln(J);
Console.writeln("or");
Console.pause();
Z:
Console.clear();
Console.writeln("GCD of");
Console.writeln(X);
Console.writeln("and");
Console.writeln(Y);
Console.writeln("is");
Console.writeln(I);
}
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