Maven:在哪里为tomcat-maven-plugin添加生成的资源？

Question

src/main/webapp我的项目目录中有CSS和JavaScript文件.我想加入这些资源的加入和缩小版本到我的WAR文件和tomcat-maven-plugin拾取它的地方.

我使用yuicompressor-maven-plugin创建文件并将其放入${project.build.directory}/${project.build.finalName}.它适用于maven包,并且这些资源可以用于WAR文件,但不知何故tomcat-maven-plugin根本看不到它们.我应该使用不同的目录吗？

我的pom:

    <plugins>
        <plugin>
            <groupId>org.codehaus.mojo</groupId>
            <artifactId>tomcat-maven-plugin</artifactId>
            <version>1.1</version>
            <configuration>
                <path>/MyApp</path>
                <warDirectory>${project.build.directory}/${project.build.finalName}</warDirectory>
            </configuration>
        </plugin>
        <plugin>
            <version>2.5.1</version>
            <inherited>true</inherited>
            <groupId>org.apache.maven.plugins</groupId>
            <artifactId>maven-compiler-plugin</artifactId>
            <configuration>
                <source>1.6</source>
                <target>1.6</target>
                <optimize>true</optimize>
                <debug>true</debug>
            </configuration>
        </plugin>
        <plugin>
            <groupId>org.apache.maven.plugins</groupId>
            <artifactId>maven-resources-plugin</artifactId>
            <version>2.5</version>
            <configuration>
                <encoding>UTF-8</encoding>
            </configuration>
        </plugin>
        <plugin>
            <groupId>org.apache.maven.plugins</groupId>
            <artifactId>maven-war-plugin</artifactId>
            <version>2.2</version>
            <configuration>
                <webResources>
                    <resource>
                        <directory>${basedir}/src/main/resources/META-INF</directory>
                        <filtering>true</filtering>
                        <targetPath>META-INF</targetPath>
                        <includes>
                            <include>context.xml</include>
                        </includes>
                    </resource>
                </webResources>
                <archive>
                    <addMavenDescriptor>false</addMavenDescriptor>
                    <manifest>
                        <addDefaultImplementationEntries>true</addDefaultImplementationEntries>
                        <addClasspath>true</addClasspath>
                    </manifest>
                </archive>
            </configuration>
        </plugin>
        <plugin>
            <groupId>net.alchim31.maven</groupId>
            <artifactId>yuicompressor-maven-plugin</artifactId>
            <version>1.3.0</version>
            <executions>
                <execution>
                    <phase>process-resources</phase>
                    <configuration>
                        <excludes>
                            <exclude>**/*</exclude>
                        </excludes>
                        <aggregations>
                            <aggregation>
                                <output>${project.build.directory}/${project.build.finalName}/js/commons-pack.js</output>
                                <includes>
                                    <include>${project.build.sourceDirectory}/../webapp/js1.js</include>
                                    <include>${project.build.sourceDirectory}/../webapp/js2.js</include>
                     ...

我该怎么做 mvn tomcat:run才能拿起我生成的文件？

Answer 1

用途warSourceDirectory：

<warSourceDirectory>${project.build.directory}/${project.build.finalName}</warSourceDirectory>

代替此配置属性（warDirectory）tomcat-maven-plugin：

<warDirectory>${project.build.directory}/${project.build.finalName}</warDirectory>

根据tomcat-maven-plugin文档，warSourceDirectoryWeb资源是从此处获取的，其默认值为${basedir}/src/main/webapp。这意味着，如果您未设置该属性，则需要在下生成统一/最小化的JavaScript文件${basedir}/src/main/webapp。

如果设置warSourceDirectory为输出文件夹，则意味着您需要在启动Tomcat之前生成此文件。