在点击事件上更改php变量

Question

如果用户点击按钮,我想更改php变量($ start和$ end由var b1和var b2调用).现在我知道php是服务器端,但我该怎么做呢？我读了一些关于使用$ get的内容,但我不知道如何实现它:

<?php if ( is_user_logged_in() ) { ?>
<input type="submit" value="Start Chat" id="start_chat" style="position: absolute; top: 30px; left: 10px;" />
<?php
 } ?> 

 <script>
jQuery('#start_chat').click(function(){
  $(this).data('clicked', true);
});

var b1 = '<?php echo $start; ?>';
var b2 = '<?php echo $end; ?>';


if(jQuery('#start_chat').data('clicked')) {
   // change var b1 and b2
} else {
    // do not change anything
}


</script>

<div id="eu_la">
<?php
$start = strtotime('9:30');
$end = strtotime('12:30');
$timenow = date('U'); 
if((date('w') == 4) && ($timenow >= $start && $timenow <= $end)) { // day 2 = Tuesday
  include('facut_mine.php');
   } 
  else {
do_shortcode('[upzslider usingphp=true]');
  } ?>

Answer 1

在这里你当前的代码,添加:

// change var b1 and b2
$.ajax({
    type: "POST",
    url: "chat.php",
    data: { b1: "123", b2: "456" }
});

上chat.php:

$start = $_POST['b1'];
$end = $_POST['b2'];

更新:

如果你需要在javascript中加载这里的数据:

在chat.php做这些改变:

// variables
if (!empty($_POST)) {
    $data['b1'] = $_POST['b1'];
    $data['b2'] = $_POST['b2'];
}

// to not lose them
$_SESSION['chat'] = $data;

// to keep it compatible with your old code
$start = $data['b1'];
$end = $data['b2'];

// send the JSON formatted output
echo json_encode($data);

在您的客户端代码:

// change var b1 and b2
$.ajax({
    type: "POST",
    url: "chat.php",
    dataType: 'json',
    data: { b1: "123", b2: "456" }
}).done(function(data) {
    b1 = data.b1;
    b2 = data.b2;
});

我没有测试过,但希望它有效!