我试图用变量的内容写一个文件,但如果该文件不存在则创建它:
到目前为止我得到了这个:
echo "$Logstring" >> $fileLog
Run Code Online (Sandbox Code Playgroud)
我缺少的是因为当文件不存在时会出错.if条件是否必要?
#! /bin/bash
VAR="something to put in a file"
OUT=$1
if [ ! -f "$OUT" ]; then
mkdir -p "`dirname \"$OUT\"`" 2>/dev/null
fi
echo $VAR >> $OUT
# the important step here is to make sure that the folder for the file exists
# and create it if it does not. It will remain silent if the folder exists.
Run Code Online (Sandbox Code Playgroud)
$ sh out hello/how/are/you/file.out
geee: ~/src/bash/moo
$ sh out hello/how/are/you/file.out
geee: ~/src/bash/moo
$ sh out another/file/lol.hmz
geee: ~/src/bash/moo
$ find .
.
./out
./another
./another/file
./another/file/lol.hmz
./hello
./hello/how
./hello/how/are
./hello/how/are/you
./hello/how/are/you/file.out
geee: ~/src/bash/moo
$ cat ./hello/how/are/you/file.out
something to put in a file
something to put in a file
geee: ~/src/bash/moo
$ cat ./another/file/lol.hmz
something to put in a file
Run Code Online (Sandbox Code Playgroud)
如果文件的文件夹名称中有空格,则需要转义的 " 用于 dirname。