SQL Server - 如何删除递归行

Vik*_* SE 4 sql sql-server-2008

在此输入图像描述

我有一个department表,我想选择并删除表中的所有引用行departmentid以及departmentidparent部门ID,我们假设departmentid=13.

这意味着

Departmentid         departmentidparent
13                     13
14                     13
15                     13
16                     14
17                     14
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在此,应从表中删除所有行.我很困惑,没有任何想法如何解决它.

Ric*_*iwi 7

带样品表

create table tbl (departmentid int, departmentidparent int)
insert tbl select 13,13
insert tbl select 14,13
insert tbl select 15,13
insert tbl select 16,14
insert tbl select 17,11
insert tbl select 115,17
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这是可以满足您需求的查询

;with cte as
(
select *
 from tbl
 where departmentid=13
 union all
 select tbl.*
 from tbl
 join cte on tbl.departmentidparent=cte.departmentid
 -- the next line is only required because the sample data has parent=self!
 where tbl.departmentid!=cte.departmentid
)
delete tbl
from cte
where tbl.departmentid = cte.departmentid
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