通过PHP在PostgreSQL中为给定用户生成问题

Question

我的主页中有一个URL列表,如下表所示

<a href="?questions&questions=777">link1</a>
<a href="?questions&questions=666">link2</a>

以下PHP脚本在参数中有问题$_GET.

 $dbconn = pg_connect("host=localhost port=5432 dbname=masi user=masi password=123");
 // A QUESTION SELECTED BY USER 
 // to generate the answers for the given question 
     $result = pg_prepare($dbconn, "query9", "SELECT title, answer
         FROM answers 
         WHERE questions_question_id = $1;");            // WARNINGS refer HERE
     // TODO I am not sure if the syntax is correct for parametr inside $_GET                             
     $result = pg_execute($dbconn, "query9", array($_GET["'question_id' = $questions_question_id"]));
           // Problem HERE inside the $_GET

感谢Nos和Jikhan用$ dbconn解决问题,并感谢Simon解决了这个线程的主要问题!

如何从URL中获取问题_id,以便Postgres理解查询？

Answer 1

似乎问题不是查询而是与数据库的连接(dbconn)