9 php
$sql = mysql_query("SELECT * FROM comments WHERE user = 1");
$i = 1;
while ($row = mysql_fetch_assoc($sql)) {
<p>$i. <?php echo $row['comment'] ?></p>
<div class="border"></div>
$i++;
}
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我怎么能不在<div class="border"></div>最后的评论下输出?
Tyl*_*ter 24
$sql = mysql_query("SELECT * FROM comments WHERE user = 1");
$number = mysql_num_rows($sql);
$i = 1;
while ($row = mysql_fetch_assoc($sql)) {
echo '<p>' . $i . $row['comment'] . '</p>';
if ($i < $number)
{
echo '<div class="border"></div>';
}
$i ++;
}
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使用WebDevHobo的建议.
小智 8
$sql = mysql_query("SELECT * FROM comments WHERE user = 1");
$output = array ();
while ($row = mysql_fetch_assoc($sql)) {
$output[] = $row['comment'];
}
echo join('<div class="border"></div>', $output);
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