将SQL case语句显示为不同的列

Pie*_*erk 2 sql oracle case

是否可以将WHENcase语句中的每一个都输出到自己的列中?我尝试过但没有运气.我最接近我想要的是下面.

我目前有一个查询如下:

select BH.BATCH                 as batch_number, 
       BS.TBS_DESCRIPTION       as batch_description,
       BH.NUM_VOUCHERS          as "NUM_VOUCHERS(BATCH)",
       case when VS.TVS_CODE = 1 then count(*) else 0 end as in_stock,
       case when VS.TVS_CODE = 3 then count(*) else 0 end as terminate,
       case when VS.TVS_CODE = 5 then count(*) else 0 end as in_progress,
       case when VS.TVS_CODE = 6 then count(*) else 0 end as used,
       case when VS.TVS_CODE = 8 then count(*) else 0 end as deactivate
from BATCH_HIST   bh,
     BATCH_STATUS bs,
     VOUCH_HIST   vh,
     VOUCH_STATUS vs
where substr(BH.ALLOCAT_DATE, 1, 6) = 201207
and   to_char(BH.STATUS) = BS.TBS_CODE
and   BH.BATCH = VH.BATCH
and   to_char(VH.STATUS) = VS.TVS_CODE
group by BH.BATCH,
         BS.TBS_DESCRIPTION,
         BH.NUM_VOUCHERS,
         VS.TVS_CODE
order by 1,2,3;
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这给了我以下输出,每个输出STATUS作为不同的记录:

BATCH_NUMBER  | BATCH_DESCRIPTION  | NUM_VOUCHERS(BATCH)  | IN_STOCK  | TERMINATE  | IN_PROGRESS  | USED  | DEACTIVATE
------------------------------------------------------------------------------------------------------------------------------
4413565       |  Allocate          |  100                 |  67       |  0         |  0           |  0    |  0
4413565       |  Allocate          |  100                 |  0        |  0         |  0           |  33   |  0
4413566       |  Allocate          |  100                 |  63       |  0         |  0           |  0    |  0
4413566       |  Allocate          |  100                 |  0        |  0         |  0           |  37   |  0
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我希望将它组合在一起,以便每个记录有一条记录BATCH_NUMBER:

BATCH_NUMBER  | BATCH_DESCRIPTION  | NUM_VOUCHERS(BATCH)  | IN_STOCK  | TERMINATE  | IN_PROGRESS  | USED  | DEACTIVATE
------------------------------------------------------------------------------------------------------------------------------
4413565       |  Allocate          |  100                 |  67       |  0         |  0           |  33   |  0
4413566       |  Allocate          |  100                 |  63       |  0         |  0           |  37   |  0
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Nik*_*vić 5

正如你所写的那样,表达式需要group by,但是如果你总结匹配,你可以通过以下方式从group中消除tvs_code:

select BH.BATCH                 as batch_number, 
       BS.TBS_DESCRIPTION       as batch_description,
       BH.NUM_VOUCHERS          as "NUM_VOUCHERS(BATCH)",
       sum (case when VS.TVS_CODE = 1 then 1 else 0 end) as in_stock,
       sum (case when VS.TVS_CODE = 3 then 1 else 0 end) as terminate,
       sum (case when VS.TVS_CODE = 5 then 1 else 0 end) as in_progress,
       sum (case when VS.TVS_CODE = 6 then 1 else 0 end) as used,
       sum (case when VS.TVS_CODE = 8 then 1 else 0 end) as deactivate
from BATCH_HIST   bh,
     BATCH_STATUS bs,
     VOUCH_HIST   vh,
     VOUCH_STATUS vs
where substr(BH.ALLOCAT_DATE, 1, 6) = 201207
and   to_char(BH.STATUS) = BS.TBS_CODE
and   BH.BATCH = VH.BATCH
and   to_char(VH.STATUS) = VS.TVS_CODE
group by BH.BATCH,
         BS.TBS_DESCRIPTION,
         BH.NUM_VOUCHERS
order by 1,2,3;
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