BeautifulSoup getText来自<p>,而不是后续的段落

Question

首先,对于Python来说,我是一个完全新手.但是,我编写了一段代码来查看RSS提要,打开链接并从文章中提取文本.这是我到目前为止:

from BeautifulSoup import BeautifulSoup
import feedparser
import urllib

# Dictionaries
links = {}
titles = {}

# Variables
n = 0

rss_url = "feed://www.gfsc.gg/_layouts/GFSC/GFSCRSSFeed.aspx?Division=ALL&Article=All&Title=News&Type=doc&List=%7b66fa9b18-776a-4e91-9f80-    30195001386c%7d%23%7b679e913e-6301-4bc4-9fd9-a788b926f565%7d%23%7b0e65f37f-1129-4c78-8f59-3db5f96409fd%7d%23%7bdd7c290d-5f17-43b7-b6fd-50089368e090%7d%23%7b4790a972-c55f-46a5-8020-396780eb8506%7d%23%7b6b67c085-7c25-458d-8a98-373e0ac71c52%7d%23%7be3b71b9c-30ce-47c0-8bfb-f3224e98b756%7d%23%7b25853d98-37d7-4ba2-83f9-78685f2070df%7d%23%7b14c41f90-c462-44cf-a773-878521aa007c%7d%23%7b7ceaf3bf-d501-4f60-a3e4-2af84d0e1528%7d%23%7baf17e955-96b7-49e9-ad8a-7ee0ac097f37%7d%23%7b3faca1d0-be40-445c-a577-c742c2d367a8%7d%23%7b6296a8d6-7cab-4609-b7f7-b6b7c3a264d6%7d%23%7b43e2b52d-e4f1-4628-84ad-0042d644deaf%7d"

# Parse the RSS feed
feed = feedparser.parse(rss_url)

# view the entire feed, one entry at a time
for post in feed.entries:
    # Create variables from posts
    link = post.link
    title = post.title
    # Add the link to the dictionary
    n += 1
    links[n] = link

for k,v in links.items():
    # Open RSS feed
    page = urllib.urlopen(v).read()
    page = str(page)
    soup = BeautifulSoup(page)

    # Find all of the text between paragraph tags and strip out the html
    page = soup.find('p').getText()

    # Strip ampersand codes and WATCH:
    page = re.sub('&\w+;','',page)
    page = re.sub('WATCH:','',page)

    # Print Page
    print(page)
    print(" ")

    # To stop after 3rd article, just whilst testing ** to be removed **
    if (k >= 3):
        break

这会产生以下输出:

>>> (executing lines 1 to 45 of "RSS_BeautifulSoup.py")
?Total deposits held with Guernsey banks at the end of June 2012 increased 2.1% in sterling terms by £2.1 billion from the end of March 2012 level of £101 billion, up to £103.1 billion. This is 9.4% lower than the same time a year ago.  Total assets and liabilities increased by £2.9 billion to £131.2 billion representing a 2.3% increase over the quarter though this was 5.7% lower than the level a year ago.  The higher figures reflected the effects both of volume and exchange rate factors.

The net asset value of total funds under management and administration has increased over the quarter ended 30 June 2012 by £711 million (0.3%) to reach £270.8 billion.For the year since 30 June 2011, total net asset values decreased by £3.6 billion (1.3%).

The Commission has updated the warranties on the Form REG, Form QIF and Form FTL to take into account the Commission’s Guidance Notes on Personal Questionnaires and Personal Declarations.  In particular, the following warranty (varies slightly dependent on the application) has been inserted in the aforementioned forms,

>>> 

问题是这是每篇文章的第一段,但我需要展示整篇文章.我们将非常感激地提供任何帮助.

Answer 1

你越来越近了!

# Find all of the text between paragraph tags and strip out the html
page = soup.find('p').getText()

使用find(正如您所注意到的)在找到一个结果后停止.如果你想要所有段落,你需要find_all.如果页面格式一致(只是查看一个),你也可以使用类似的东西

soup.find('div',{'id':'ctl00_PlaceHolderMain_RichHtmlField1__ControlWrapper_RichHtmlField'})

把文章的主体归零.

Answer 2

这适用于文本全部包含在<p>标签中的特定文章。由于网络是一个丑陋的地方，因此情况并非总是如此。

通常，网站将文本分散在各处，包裹在不同类型的标签中（例如可能在 a<span>或 a<div>或 an 中<li>）。

要查找 DOM 中的所有文本节点，您可以使用soup.find_all(text=True).

这将返回一些不需要的文本，例如<script>和<style>标签的内容。您需要过滤掉不需要的元素的文本内容。

blacklist = [
  'style',
  'script',
  # other elements,
]

text_elements = [t for t in soup.find_all(text=True) if t.parent.name not in blacklist]

如果您正在使用一组已知的标签，则可以使用相反的方法进行标记：

whitelist = [
  'p'
]

text_elements = [t for t in soup.find_all(text=True) if t.parent.name in whitelist]

Answer 3

获取文本

htmldata = getdata("https://www.geeksforgeeks.org/how-to-automate-an-excel-sheet-in-python/?ref=feed") 
soup = BeautifulSoup(htmldata, 'html.parser') 
data = '' 
for data in soup.find_all("p"): 
    print(data.get_text())