如何检测iPhone 5(宽屏设备)？

Question

我刚刚升级到XCode 4.5 GM,发现你现在可以将"4"Retina'大小应用到故事板中的视图控制器.

现在,如果我想创建一个在iPhone 4和5上运行的应用程序,当然我必须构建每个窗口两次,但我还必须检测用户是否有一个3.5"或4"屏幕的iPhone,然后应用视图.

我该怎么办？

Answer 1

首先,您不应重建所有视图以适应新屏幕,也不应对不同屏幕尺寸使用不同视图.

使用iOS 的自动调整大小功能,以便您的视图可以调整,并适应任何屏幕大小.

这不是很难,请阅读一些相关的文档.它会为你节省很多时间.

iOS 6还提供了相关的新功能,但目前仍在NDA下.如果您可以访问它,
请务必阅读Apple Developer网站上的API更新日志.

编辑:由于iOS 6现已用完,请检查新的AutoLayout功能.

也就是说,如果你真的需要检测iPhone 5,你可以简单地依赖屏幕尺寸.

[ [ UIScreen mainScreen ] bounds ].size.height

iPhone 5的屏幕高度为568.
您可以想象一个宏,以简化所有这些:

#define IS_IPHONE_5 ( fabs( ( double )[ [ UIScreen mainScreen ] bounds ].size.height - ( double )568 ) < DBL_EPSILON )

如fabsH2CO3的评论中所指出的,在比较浮点时,使用epsilon可以防止精度错误.

所以从现在开始,你可以在标准的if/else语句中使用它:

if( IS_IPHONE_5 )
{}
else
{}

编辑 - 更好的检测

正如一些人所说,这只能检测宽屏,而不是真正的iPhone 5.

iPod touch的下一个版本也可能有这样的屏幕,所以我们可能会使用另一组宏.

让我们重命名原始宏IS_WIDESCREEN:

#define IS_WIDESCREEN ( fabs( ( double )[ [ UIScreen mainScreen ] bounds ].size.height - ( double )568 ) < DBL_EPSILON )

让我们添加模型检测宏:

#define IS_IPHONE ( [ [ [ UIDevice currentDevice ] model ] isEqualToString: @"iPhone" ] )
#define IS_IPOD   ( [ [ [ UIDevice currentDevice ] model ] isEqualToString: @"iPod touch" ] )

这样,我们可以确保我们有一个iPhone型号和一个宽屏幕,我们可以重新定义IS_IPHONE_5宏:

#define IS_IPHONE_5 ( IS_IPHONE && IS_WIDESCREEN )

另请注意,正如@ LearnCocos2D所述,如果应用程序未针对iPhone 5屏幕进行优化(缺少Default-568h@2x.png图像),则此宏将无法工作,因为屏幕大小仍为320x480一件事.

我不认为这可能是一个问题,因为我不明白为什么我们想要在非优化的应用程序中检测iPhone 5.

重要信息 - iOS 8支持

在iOS 8上,类的bounds属性UIScreen现在反映了设备方向.
很明显,以前的代码不会开箱即用.

为了解决这个问题,您可以简单地使用新nativeBounds属性,而不是bounds因为它不会随方向而改变,因为它基于纵向模式.
请注意,尺寸nativeBounds是以像素为单位测量的,因此对于iPhone 5,高度将是1136而不是568.

如果您还要定位iOS 7或更低版​​本,请务必使用功能检测,因为nativeBounds在iOS 8之前调用会导致您的应用崩溃:

if( [ [ UIScreen mainScreen ] respondsToSelector: @selector( nativeBounds ) ] )
{
    /* Detect using nativeBounds - iOS 8 and greater */
}
else
{
    /* Detect using bounds - iOS 7 and lower */
}

您可以通过以下方式调整以前的宏:

#define IS_WIDESCREEN_IOS7 ( fabs( ( double )[ [ UIScreen mainScreen ] bounds ].size.height - ( double )568 ) < DBL_EPSILON )
#define IS_WIDESCREEN_IOS8 ( fabs( ( double )[ [ UIScreen mainScreen ] nativeBounds ].size.height - ( double )1136 ) < DBL_EPSILON )
#define IS_WIDESCREEN      ( ( [ [ UIScreen mainScreen ] respondsToSelector: @selector( nativeBounds ) ] ) ? IS_WIDESCREEN_IOS8 : IS_WIDESCREEN_IOS7 )

显然,如果您需要检测iPhone 6或6 Plus,请使用相应的屏幕尺寸.

最后的说明

意见和建议已纳入本文.
感谢大家.

Answer 2

针对SDK和OS的任何组合进行测试和设计:

迅速

添加了iPad类型.iPad 2和iPad mini是非视网膜iPad.iPad Mini 2及以上,iPad 3,iPad Air,Air 2,Air 3和iPad Pro 9.7具有相同的1024逻辑分辨率.iPad Pro的maxLength为1366. 参考

import UIKit

public enum DisplayType {
    case unknown
    case iphone4
    case iphone5
    case iphone6
    case iphone6plus
    case iPadNonRetina
    case iPad
    case iPadProBig
    static let iphone7 = iphone6
    static let iphone7plus = iphone6plus
}

public final class Display {
    class var width:CGFloat { return UIScreen.main.bounds.size.width }
    class var height:CGFloat { return UIScreen.main.bounds.size.height }
    class var maxLength:CGFloat { return max(width, height) }
    class var minLength:CGFloat { return min(width, height) }
    class var zoomed:Bool { return UIScreen.main.nativeScale >= UIScreen.main.scale }
    class var retina:Bool { return UIScreen.main.scale >= 2.0 }
    class var phone:Bool { return UIDevice.current.userInterfaceIdiom == .phone }
    class var pad:Bool { return UIDevice.current.userInterfaceIdiom == .pad }
    class var carplay:Bool { return UIDevice.current.userInterfaceIdiom == .carPlay }
    class var tv:Bool { return UIDevice.current.userInterfaceIdiom == .tv }
    class var typeIsLike:DisplayType {
        if phone && maxLength < 568 {
            return .iphone4
        }
        else if phone && maxLength == 568 {
                return .iphone5
        }
        else if phone && maxLength == 667 {
            return .iphone6
        }
        else if phone && maxLength == 736 {
            return .iphone6plus
        }
        else if pad && !retina {
            return .iPadNonRetina
        }
        else if pad && retina && maxLength == 1024 {
            return .iPad
        }
        else if pad && maxLength == 1366 {
            return .iPadProBig
        }
        return .unknown
    }
}

在操作中查看它 https://gist.github.com/hfossli/bc93d924649de881ee2882457f14e346

注意:如果例如iPhone 6处于缩放模式,则UI是iPhone 5的放大版本.这些功能不是确定设备类型,而是显示模式因此iPhone 5是此示例中的期望结果.

Objective-C的

#define IS_IPAD (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad)
#define IS_IPHONE (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
#define IS_RETINA ([[UIScreen mainScreen] scale] >= 2.0)

#define SCREEN_WIDTH ([[UIScreen mainScreen] bounds].size.width)
#define SCREEN_HEIGHT ([[UIScreen mainScreen] bounds].size.height)
#define SCREEN_MAX_LENGTH (MAX(SCREEN_WIDTH, SCREEN_HEIGHT))
#define SCREEN_MIN_LENGTH (MIN(SCREEN_WIDTH, SCREEN_HEIGHT))
#define IS_ZOOMED (IS_IPHONE && SCREEN_MAX_LENGTH == 736.0)

#define IS_IPHONE_4_OR_LESS (IS_IPHONE && SCREEN_MAX_LENGTH < 568.0)
#define IS_IPHONE_5 (IS_IPHONE && SCREEN_MAX_LENGTH == 568.0)
#define IS_IPHONE_6 (IS_IPHONE && SCREEN_MAX_LENGTH == 667.0)
#define IS_IPHONE_6P (IS_IPHONE && SCREEN_MAX_LENGTH == 736.0)

用法:http://pastie.org/9687735

注意:如果例如iPhone 6处于缩放模式,则UI是iPhone 5的放大版本.这些功能不是确定设备类型,而是显示模式因此iPhone 5是此示例中的期望结果.

Answer 3

真的很简单的解决方案

if(UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
{
    CGSize result = [[UIScreen mainScreen] bounds].size;
    if(result.height == 480)
    {
        // iPhone Classic
    }
    if(result.height == 568)
    {
        // iPhone 5
    }
}

Answer 4

我们现在需要考虑iPhone 6和6Plus屏幕尺寸.这是一个更新的答案

if(UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
{
    //its iPhone. Find out which one?

    CGSize result = [[UIScreen mainScreen] bounds].size;
    if(result.height == 480)
    {
        // iPhone Classic
    }
    else if(result.height == 568)
    {
        // iPhone 5
    }
    else if(result.height == 667)
    {
        // iPhone 6
    }
   else if(result.height == 736)
    {
        // iPhone 6 Plus
    }
}
else
{
     //its iPad
}

一些有用的信息

iPhone 6 Plus   736x414 points  2208x1242 pixels    3x scale    1920x1080 physical pixels   401 physical ppi    5.5"
iPhone 6        667x375 points  1334x750 pixels     2x scale    1334x750 physical pixels    326 physical ppi    4.7"
iPhone 5        568x320 points  1136x640 pixels     2x scale    1136x640 physical pixels    326 physical ppi    4.0"
iPhone 4        480x320 points  960x640 pixels      2x scale    960x640 physical pixels     326 physical ppi    3.5"
iPhone 3GS      480x320 points  480x320 pixels      1x scale    480x320 physical pixels     163 physical ppi    3.5"

Answer 5

我冒昧通过Macmade把宏成C函数,因为它检测到正确命名为宽屏可用性和不必然是iPhone 5.

如果项目不包含Default-568h@2x.png,宏也不会检测到在iPhone 5上运行.如果没有新的默认图像,iPhone 5将报告常规的480x320屏幕尺寸(以磅为单位).因此,检查不仅适用于宽屏可用性,还适用于宽屏模式.

BOOL isWidescreenEnabled()
{
    return (BOOL)(fabs((double)[UIScreen mainScreen].bounds.size.height - 
                                               (double)568) < DBL_EPSILON);
}

Answer 6

这是我们的代码,测试通过ios7/ios8 for iphone4,iphone5,ipad,iphone6,iphone6p,无论是在设备还是模拟器上:

#define IS_IPAD (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad)
#define IS_IPHONE (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) // iPhone and       iPod touch style UI

#define IS_IPHONE_5_IOS7 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 568.0f)
#define IS_IPHONE_6_IOS7 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 667.0f)
#define IS_IPHONE_6P_IOS7 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 736.0f)
#define IS_IPHONE_4_AND_OLDER_IOS7 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height < 568.0f)

#define IS_IPHONE_5_IOS8 (IS_IPHONE && ([[UIScreen mainScreen] nativeBounds].size.height/[[UIScreen mainScreen] nativeScale]) == 568.0f)
#define IS_IPHONE_6_IOS8 (IS_IPHONE && ([[UIScreen mainScreen] nativeBounds].size.height/[[UIScreen mainScreen] nativeScale]) == 667.0f)
#define IS_IPHONE_6P_IOS8 (IS_IPHONE && ([[UIScreen mainScreen] nativeBounds].size.height/[[UIScreen mainScreen] nativeScale]) == 736.0f)
#define IS_IPHONE_4_AND_OLDER_IOS8 (IS_IPHONE && ([[UIScreen mainScreen] nativeBounds].size.height/[[UIScreen mainScreen] nativeScale]) < 568.0f)

#define IS_IPHONE_5 ( ( [ [ UIScreen mainScreen ] respondsToSelector: @selector( nativeBounds ) ] ) ? IS_IPHONE_5_IOS8 : IS_IPHONE_5_IOS7 )
#define IS_IPHONE_6 ( ( [ [ UIScreen mainScreen ] respondsToSelector: @selector( nativeBounds ) ] ) ? IS_IPHONE_6_IOS8 : IS_IPHONE_6_IOS7 )
#define IS_IPHONE_6P ( ( [ [ UIScreen mainScreen ] respondsToSelector: @selector( nativeBounds ) ] ) ? IS_IPHONE_6P_IOS8 : IS_IPHONE_6P_IOS7 )
#define IS_IPHONE_4_AND_OLDER ( ( [ [ UIScreen mainScreen ] respondsToSelector: @selector( nativeBounds ) ] ) ? IS_IPHONE_4_AND_OLDER_IOS8 : IS_IPHONE_4_AND_OLDER_IOS7 )

Answer 7

我使用了hfossli的答案并将其翻译成Swift

let IS_IPAD = UIDevice.currentDevice().userInterfaceIdiom == .Pad
let IS_IPHONE = UIDevice.currentDevice().userInterfaceIdiom == .Phone
let IS_RETINA = UIScreen.mainScreen().scale >= 2.0

let SCREEN_WIDTH = UIScreen.mainScreen().bounds.size.width
let SCREEN_HEIGHT = UIScreen.mainScreen().bounds.size.height
let SCREEN_MAX_LENGTH = max(SCREEN_WIDTH, SCREEN_HEIGHT)
let SCREEN_MIN_LENGTH = min(SCREEN_WIDTH, SCREEN_HEIGHT)

let IS_IPHONE_4_OR_LESS = (IS_IPHONE && SCREEN_MAX_LENGTH < 568.0)
let IS_IPHONE_5 = (IS_IPHONE && SCREEN_MAX_LENGTH == 568.0)
let IS_IPHONE_6 = (IS_IPHONE && SCREEN_MAX_LENGTH == 667.0)
let IS_IPHONE_6P = (IS_IPHONE && SCREEN_MAX_LENGTH == 736.0)

Answer 8

这是我的cocos2d项目的宏.对于其他应用应该是相同的.

#define WIDTH_IPAD 1024
#define WIDTH_IPHONE_5 568
#define WIDTH_IPHONE_4 480
#define HEIGHT_IPAD 768
#define HEIGHT_IPHONE 320

#define IS_IPHONE (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
#define IS_IPAD (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad)

//width is height!
#define IS_IPHONE_5 ( [ [ UIScreen mainScreen ] bounds ].size.height == WIDTH_IPHONE_5 )
#define IS_IPHONE_4 ( [ [ UIScreen mainScreen ] bounds ].size.height == WIDTH_IPHONE_4 )

#define cp_ph4(__X__, __Y__) ccp(cx_ph4(__X__), cy_ph4(__Y__))
#define cx_ph4(__X__) (IS_IPAD ? (__X__ * WIDTH_IPAD / WIDTH_IPHONE_4) : (IS_IPHONE_5 ? (__X__ * WIDTH_IPHONE_5 / WIDTH_IPHONE_4) : (__X__)))
#define cy_ph4(__Y__) (IS_IPAD ? (__Y__ * HEIGHT_IPAD / HEIGHT_IPHONE) : (__Y__))

#define cp_pad(__X__, __Y__) ccp(cx_pad(__X__), cy_pad(__Y__))
#define cx_pad(__X__) (IS_IPAD ? (__X__) : (IS_IPHONE_5 ? (__X__ * WIDTH_IPHONE_5 / WIDTH_IPAD) : (__X__ * WIDTH_IPHONE_4 / WIDTH_IPAD)))
#define cy_pad(__Y__) (IS_IPAD ? (__Y__) : (__Y__ * HEIGHT_IPHONE / HEIGHT_IPAD))

Answer 9

if ((int)[[UIScreen mainScreen] bounds].size.height == 568)
{
    // This is iPhone 5 screen
} else {
    // This is iPhone 4 screen
}