pycassa TypeError:str或unicode,无法执行cassandra插入

Question

我的脚本是python,cassandra是数据stax社区版.

TypeError: A str or unicode value was expected, but int was received instead (3902503)

这是我在尝试插入cassandra列族时遇到的错误.

代码如下:

for x in feed:
    cf.insert(uuid.uuid4(), x)

x是一个简单的数组,形式为"{key:value}"

错误日志表明:

    Traceback (most recent call last):
      File "C:\Users\me\Desktop\pro1\src\pro1.py", line 73, in <module>
        str("swf"): str("aws")
      File "c:\Python27\lib\site-packages\pycassa\columnfamily.py", line 969, in insert
        mut_list = self._make_mutation_list(columns, timestamp, ttl)
      File "c:\Python27\lib\site-packages\pycassa\columnfamily.py", line 504, in _make_mutation_list
        columns.iteritems())
      File "c:\Python27\lib\site-packages\pycassa\columnfamily.py", line 503, in <lambda>
        return map(lambda (c, v): Mutation(self._make_cosc(_pack_name(c), _pack_value(v, c), timestamp, ttl)),
      File "c:\Python27\lib\site-packages\pycassa\columnfamily.py", line 462, in _pack_value
        return packer(value)
      File "c:\Python27\lib\site-packages\pycassa\marshal.py", line 231, in pack_bytes
        % (v.__class__.__name__, str(v)))
    TypeError: A str or unicode value was expected, but int was received instead (3902503)        

似乎有一些我在这里失踪的东西...这就是为什么我来这里问专家!

Answer 1

确保您的值与您的柱族类型匹配。看来您的列族要么是 BytesType，要么没有与之关联的类型，因此 pycassa 将只接受字符串值。您可以将所有值映射到str带有嵌套字典理解的列表理解（后者需要 python 2.7 及更高版本）：

cf.insert(uuid.uuid4(), [{k: str(v) for k, v in d.iteritems()} for d in x])