如何仅对某些文件类型运行'git diff --check'

Question

我一直无法弄清楚如何在提交中仅在Python文件上运行'git diff --check'。我有3个文件的提交：

$ git show --name-only
...
tools/gitHooks/preReceive.py
tools/gitHooks/unittests/testPreReceive.py
Makefile

最后2个文件中包含尾随空格。

$ git diff --check HEAD~1 HEAD
tools/gitHooks/unittests/testPreReceive.py:75: trailing whitespace.
+newmock = Mock()
Makefile:41: new blank line at EOF.

我想将空白检查限制为仅Python文件。这样做可以给我正确的文件：

$ git diff --name-only HEAD~1 HEAD | grep ".py"
tools/gitHooks/preReceive.py
tools/gitHooks/unittests/testPreReceive.py

但是，当我将文件名通过管道传递到“ git diff --check”（带有或不带有xargs）时，我得到了错误的输出。

$ git diff --name-only HEAD~1 HEAD | grep ".py" | xargs git diff --check HEAD~1 HEAD --
$
$ git diff --name-only HEAD~1 HEAD | grep ".py" | git diff --check HEAD~1 HEAD --
tools/gitHooks/unittests/testPreReceive.py:75: trailing whitespace.
+newmock = Mock()
Makefile:41: new blank line at EOF.

我也尝试过此方法以及它的一些变体，但是没有运气：

$ git diff --check HEAD~1 HEAD -- "*.py"
$

有人可以帮忙吗？我觉得我已经接近答案了。

Answer 1

来自原始海报：

原来我使用了错误的 grep。

$ git diff --name-only HEAD~1 HEAD | grep \.py$ | \
$ xargs git diff --check HEAD~1 HEAD --
tools/gitHooks/unittests/testPreReceive.py:75: trailing whitespace.
+newmock = Mock()