Android:SQLite使用错误的数据库

Question

我在我的android java项目中使用多个SQLite数据库.第一个(登录)工作正常,使用以下代码,我正在关闭连接.但是,在下一页上,我正在调用一个使用不同数据库的函数,但它似乎仍然引用第一个数据库而不是新数据库.我收到这个错误:

09-14 13:18:01.990: I/SqliteDatabaseCpp(10035): sqlite returned: error code = 1, msg = no such table:
 NextID, db=/mnt/extSdCard/DirectEnquiries/AuditingData/Static/Users

哪个是对的,NextID不在用户中.

以下是使用Users表的登录页面的代码:

if(String.valueOf(loginCount).equals("2")) {

        File dbfile = new File(Global.StaticDB + "/Users" ); 
        SQLiteDatabase db = SQLiteDatabase.openOrCreateDatabase(dbfile, null);

        Cursor c = db.rawQuery("SELECT UserID from Users where UserID like '" + txtUsername.getText().toString().trim() + "' AND Password like '" + txtPassword.getText().toString().trim() + "'", null); 
        c.moveToFirst();

        if(c.getCount() > 0) {
            Global.Username = c.getString(c.getColumnIndex("UserID"));
            Global.currentDB = spnLocation.getSelectedItem().toString();
            Global.currentDBfull = Global.sctArea + Global.currentDB;

            db.close();
            Context context = getApplicationContext();
            CharSequence text = "Logged In";
            int duration = Toast.LENGTH_SHORT;
            Toast toast = Toast.makeText(context, text, duration);
            toast.show();
            Intent ShowMainPage = new Intent(view.getContext(), MainPage.class);
            startActivityForResult(ShowMainPage, 0);


        }

下一页是使用这个:

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main_page);
    TextView txt = (TextView) findViewById(R.id.textView1);
    txt.setText(Global.Username);
    TextView dbtxt = (TextView) findViewById(R.id.txtDB);
    dbtxt.setText(Functions.getNextID("StationObjects"));

}

功能是:

public static int getNextID(String tablename) {
    Log.e("Current DB is: ", Global.currentDBfull);
    File dbfile = new File(Global.currentDBfull); 
    SQLiteDatabase dbF = SQLiteDatabase.openOrCreateDatabase(dbfile, null);

    int rtnID=(int)DatabaseUtils.longForQuery(dbF,"Select NxtNumber from NextID where NxtTable like '" + tablename + "'",null);    
    rtnID += 1;
    //db.rawQuery("update NextID set NxtNumber = '" + rtnID + "' where NxtTable like 'StationObjects'", null);
    dbF.close();
    return rtnID;
}

如何确保它使用第二个数据库而不是第一个？汤姆

Answer 1

您可以尝试使用以下格式打开和关闭数据库：

private static String DB_PATH = "/data/data/PACKAGE_NAME/databases/DATABASE_NAME.db";
private static SQLiteDatabase db;
db = SQLiteDatabase.openDatabase(DB_PATH, null, SQLiteDatabase.OPEN_READONLY);
// RUN YOUR QUERIES ETC
db.close()

对于 2 个数据库的情况，您需要定义 2 个 DB_PATH 并在相关的地方引用它们。

希望这有帮助，L & L 合作伙伴