在mysql中获取连续记录

Question

我的表结构如下

ID           user_id         win 
1              1               1 
2              1               1 
3              1               0 
4              1               1 
5              2               1 
6              2               0 
7              2               0 
8              2               1 
9              1               0 
10             1               1 
11             1               1 
12             1               1 
13             1               1
14             3               1 

我希望在mysql.like中为user_id = 1获得连续获胜(win = 1),对于user_id = 2(记录id = 5),它应该返回4(记录id 10,11,12,13),它应该返回1.

我可以在为每个用户重新审阅记录后在php中执行此操作,但我不知道如何使用查询到mysql来执行此操作.

使用php或mysql在性能方面也会更好.任何帮助将不胜感激.谢谢!!!

Answer 1

不确定您是否已设法使其他查询正常工作，但这是我的尝试，绝对有效 - Sqlfiddle来证明这一点。

set @x=null;
set @y=0;

select sub.user_id as user_id,max(sub.streak) as streak
from
(
select 
case when @x is null then @x:=user_id end,
case 
when win=1 and @x=user_id then @y:=@y+1 
when win=0 and @x=user_id then @y:=0 
when win=1 and @x<>user_id then @y:=1
when win=0 and @x<>user_id then @y:=0
end as streak,
@x:=user_id as user_id
from your_table
) as sub
group by sub.user_id

如何让它在 PHP 页面上工作并进行测试以查看是否获得正确的结果如下，我还对查询进行了一些优化：

mysql_query("set @y=0");
$query=mysql_query("select sub.user_id as user_id,max(sub.streak) as streak
from
(
select
case 
when win=1 and @x=user_id then @y:=@y+1 
when win=0 and @x=user_id then @y:=0 
when win=1 and @x<>user_id then @y:=1
when win=0 and @x<>user_id then @y:=0
end as streak,
@x:=user_id as user_id
from your_table
) as sub
group by sub.user_id");
while($row=mysql_fetch_assoc($query)){
print_r($row);}