链接服务器上的标识插入失败

Question

我想使用存储过程将我的测试数据库中的表复制到具有相同ID /身份的链接服务器但我无法使其工作..我已设置IDENTITY_INSERT为ON但它仍然抱怨ID列.

这是我的程序:

CREATE PROCEDURE [dbo].[TEST2PROD_CopyUIDataSServer]
AS Begin
declare @sql nvarchar(max)
-- First truncate target table
set @sql = 'EXEC [LINKEDSERVER].tempdb.sys.sp_sqlexec' + char(39)+ 'TRUNCATE Table [ProductManager].dbo.[UIData]' + char(39)+  ';'
---- SET IDENTITY_INSERT ON
set @sql = @sql + 'EXEC [LINKEDSERVER].tempdb.sys.sp_sqlexec' + char(39)+ 'SET IDENTITY_INSERT [ProductManager].[dbo].[UIData] ON' + char(39)+  ';'
---- INSERT UIDATA records from DB1 into linked server DB2
set @sql = @sql + 'WITH TestData as (SELECT * from ProductManager.dbo.UIData UID)' + NCHAR(13)+  'INSERT INTO   [LINKEDSERVER].[ProductManager].[dbo].[UIData]' + NCHAR(13) + 'select * from TestData;'
print @sql
exec (@sql) 
end

但是当我执行SP时它会给我以下错误:

用于链接服务器的OLE DB提供程序"SQLNCLI10"....无法INSERT INTO表"[LINKEDSERVER].[ProductManager].[dbo].[UIData]"因为列"Id".用户无权写入列.

链接的服务器属性RPC和RPC out设置为true.我希望有些男生可以帮助我吗？

更新:我决定将事情分开,首先我将数据从本地服务器复制到链接服务器TEMP_TABLE,我不需要处理IDENTITY问题.

然后我在链接/远程服务器上写了一个存储过程,因为我没有使用,SELECT *而是指定列列表.这可能会在SP的本地服务器上运行,但我没有时间或兴趣检查它..

USE [ProductManager]
GO
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE PROCEDURE [dbo].[TEST2PROD_CopyBaseTables]
AS BEGIN
DECLARE @DestTable VARCHAR(50)
DECLARE @DestPath VARCHAR(50)
DECLARE @SrceTable VARCHAR(255)
declare @sql nvarchar(max)
DECLARE @columnList varchar(max)
DECLARE @err int

Begin TRY

declare @comma_delimited_list varchar(4000) 
--- FIRST TRY WITH ONE TABLE, EXTENDABLE...
set @comma_delimited_list = 'UIData' 

declare @cursor cursor 
set @cursor = cursor static for  
  select * from dbo.Split(@comma_delimited_list,',') a 

declare @naam varchar(50)
open @cursor 
while 1=1 begin 
  fetch next from @cursor into @DestTable
  if @@fetch_status <> 0 break 

    --Create tablenames
    SET @SrceTable = '[ProductManager].[dbo].TEMP_' + @DestTable
    SET @DestPath = '[ProductManager].[dbo].'+ @DestTable 
    print @srceTable;
    print @DestTable;

    --Truncate target table
    set @sql ='TRUNCATE TABLE '+ @DestPath + ';'

    --Insert statement needs column names
    set @columnList =''
    SELECT  @columnList = coalesce(@columnList + '[' + name + '],','') FROM sys.columns Where OBJECT_NAME(OBJECT_ID) = @DestTable
    if RIGHT(RTRIM(@columnList),1) = ',' 
    begin
        SET @columnList = LEFT(@columnList, LEN(@columnList) - 1) 
    end

    --Transfer data from source table 2 destination
     set @sql = @sql + ' SET IDENTITY_INSERT ' + @DestPath + ' ON;' + ' INSERT INTO ' + @DestPath + '(' + @columnList + ') SELECT ' + @columnList + ' FROM ' + @SrceTable

    print @sql;

    exec (@sql)
end 
-- not strictly necessary w/ cursor variables since the will go out of scope like a normal var 
close @cursor 
deallocate @cursor 

End Try
Begin Catch
 declare @ErrorMsg nvarchar(MAX);
 select @ErrorMsg =  ERROR_MESSAGE();

SELECT @err = @@error IF @err <> 0 Return @err
end Catch
END

Answer 1

IDENTITY_INSERT不适用于链接服务器AFAIK,除非您执行包含SET IDENTITY_INSERT批处理中的动态SQL 或在远程服务器上有一些代码(例如Stored Proc)为您执行此操作.

这IDENTITY_INSERT是每个会话(请参阅MSDN),当您使用远程服务器时,这可能与您执行的语句处于不同的会话中[LINKEDSERVER].tempdb.sys.sp_sqlexec,这会导致它在您看到它时发生故障.

Answer 2

您可以插入与标识值插入到表中标识列一个上链接服务器的"切换到"的把戏.

如果你还没有使用"SWITCH TO"技巧来添加和删除列上的标识,那么即使在大型表格上也是如此!

从概念上讲,您只需创建一个与您想要的表完全相同的新SCHEMA INSERT,而无需定义标识.然后将表格切换到该SCHEMA并执行INSERT.然后切换回定义了标识的SCHEMA.
以下示例已在AZURE的链接服务器上进行了测试.使用"SWITCH TO"的所有注意事项(索引必须相同,删除并重新创建外键等)

要进行测试,您可以在链接的Azure SQL Server数据库上运行下面的完整脚本.您需要使用[LINKED_SERVER_NAME]和[DATABASE_NAME]替换您的值进行查找/替换.在非Azure数据库上,您可能需要在表创建中添加"ON PRIMARY".

--Let's setup the example by creating a table with an IDENTITY column on the Linked Server
EXEC('
CREATE TABLE [DATABASE_NAME].[dbo].[Example_Table](
    [ID] [int] IDENTITY(1,1) NOT NULL,
    [Name] [nchar](10) NULL
)
 '
) AT [LINKED_SERVER_NAME]

--INSERT some data into the table
INSERT INTO [LINKED_SERVER_NAME].[DATABASE_NAME].[dbo].[Example_Table] ([Name]) VALUES ('Travis')
INSERT INTO [LINKED_SERVER_NAME].[DATABASE_NAME].[dbo].[Example_Table] ([Name]) VALUES ('Mike')

-- Looks good
SELECT * FROM [LINKED_SERVER_NAME].[DATABASE_NAME].[dbo].[Example_Table]

GO


-- Create a TABLE with an identical schema, without the identity defined
EXEC('
CREATE TABLE [DATABASE_NAME].[dbo].[Example_Table_temp](
    [ID] [int] NOT NULL,
    [Name] [nchar](10) NULL
)
 '
) AT [LINKED_SERVER_NAME]

--Now Use the "SWITCH TO" to move the data to the new table
EXEC('
 ALTER TABLE [DATABASE_NAME].[dbo].[Example_Table] SWITCH TO [DATABASE_NAME].[dbo].[Example_Table_temp]
  '
) AT [LINKED_SERVER_NAME]


--Drop the old table (It should now be empty, but you may want to verify that if you are unsure here)
EXEC('
 DROP TABLE [DATABASE_NAME].[dbo].[Example_Table]
 '
) AT [LINKED_SERVER_NAME] 

--Rename the new table back to the old table name
-- NOTE the lack of database and owner identifiers in the new name
-- NOTE the use of double single qoutes (ESCAPED single quotes)
EXEC('
  EXEC sp_rename ''[DATABASE_NAME].[dbo].Example_Table_temp'',''Example_Table''
   '
) AT [LINKED_SERVER_NAME] 


  -- Now do your IDENTITY INSERTs !!!!

 INSERT INTO [LINKED_SERVER_NAME].[DATABASE_NAME].[dbo].[Example_Table] (ID,[Name]) VALUES (888,'Travis')
 INSERT INTO [LINKED_SERVER_NAME].[DATABASE_NAME].[dbo].[Example_Table] (ID,[Name]) VALUES (999,'Mike')

 --Verify they got put in
SELECT * FROM [LINKED_SERVER_NAME].[DATABASE_NAME].[dbo].[Example_Table] 


  --Now let's switch it back to our SCHEMA with an IDENTITY

  EXEC('
CREATE TABLE [DATABASE_NAME].[dbo].[Example_Table_temp](
    [ID] [int] IDENTITY(1,1) NOT NULL,
    [Name] [nchar](10) NULL
)

 ALTER TABLE [DATABASE_NAME].[dbo].[Example_Table] SWITCH TO [DATABASE_NAME].[dbo].[Example_Table_temp]

 DROP TABLE [DATABASE_NAME].[dbo].[Example_Table]

  EXEC sp_rename ''[DATABASE_NAME].[dbo].Example_Table_temp'',''Example_Table''
     '
) AT [LINKED_SERVER_NAME] 

--Data is still there
 SELECT * FROM [LINKED_SERVER_NAME].[DATABASE_NAME].[dbo].[Example_Table] 
 GO
 -- And note you can no longer INSERT the IDENTITY
 INSERT INTO [LINKED_SERVER_NAME].[DATABASE_NAME].[dbo].[Example_Table] (ID,[Name]) VALUES (45,'Travis')
GO