MySQL语法错误,但仅限于通过PHP使用时

2xA*_*xAA 5 php mysql syntax

我正在尝试在我的数据库中重新哈希用户ID,但我遇到了困难.

<?php
include("session.php");
include("functions.php");
$conn = ConnectMySQL();
setTimezone($session->username);

$sql = "SELECT username, userid FROM users";
$result = mysql_query($sql) or die(mysql_error());
while($rows = mysql_fetch_array($result)){
    $username = $rows['username'];
    $old = mysql_real_escape_string($rows['userid']);
    $new = mysql_real_escape_string($session->generateRandID());

    $moresql = "START TRANSACTION;
                UPDATE users SET userid='$new' WHERE userid='$old';
                UPDATE comments SET user='$new' WHERE user='$old';
                UPDATE forum_posts SET poster_name='$new' WHERE poster_name='$old';
                UPDATE forum_topics SET topic_poster_name='$new' WHERE topic_poster_name='$old';
                UPDATE images SET author='$new' WHERE author='$old';
                UPDATE likes SET user='$new' WHERE user='$old';
                UPDATE music SET author='$new' WHERE author='$old';
                UPDATE ratings SET user='$new' WHERE user='$old';
                COMMIT;";
    $newresult = mysql_query($moresql) or die(mysql_error());
    if(!$newresult){echo "There was a problem with changing $username's hash. \n";}
    else{echo "Changed $username's hash<i>!</i> \n";}
}
mysql_close($conn);
?>
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整个查询通过PHPMyAdmin完全正常工作,显然只返回零行.但是当我尝试将实际值通过它与PHP一起使用时,它会变得很糟糕:

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'UPDATE users SET userid='b8aca4b680707453fa4dfe1bf1d0fddb' WHERE userid='8' at line 2
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没有其他错误 - 我不知道它是什么.提前致谢,

山姆

rat*_*oss 7

mysql_query()不支持多个查询.您必须一次执行一个查询.请参见http://php.net/manual/en/function.mysql-query.php