通过MSBuild构建具有不同平台的Visual Studio项目

Question

我有3个配置项目:

• 项目A:调试| AnyCPU,发布| AnyCPU
• 项目B:调试| AnyCPU,发布| AnyCPU
• 项目C:调试| x86,调试| x64,发布| x86,发布| x64

项目C具有依赖关系中的B,并且B具有依赖关系中的A. (A < - B < - C)

我使用*.bat文件从命令行构建它:

msbuild A.csproj /target:Build /property:Configuration=Debug;Platform=AnyCPU /verbosity:minimal
msbuild A.csproj /target:Build /property:Configuration=Release;Platform=AnyCPU /verbosity:minimal<br/>
msbuild B.csproj /target:Build /property:Configuration=Debug;Platform=AnyCPU /verbosity:minimal
msbuild B.csproj /target:Build /property:Configuration=Release;Platform=AnyCPU /verbosity:minimal
msbuild C.csproj /target:Build /property:Configuration=Debug;Platform=x86 /verbosity:minimal
msbuild C.csproj /target:Build /property:Configuration=Release;Platform=x86 /verbosity:minimal
msbuild C.csproj /target:Build /property:Configuration=Debug;Platform=x64 /verbosity:minimal
msbuild C.csproj /target:Build /property:Configuration=Release;Platform=x64 /verbosity:minimal

并收到错误:

C:\ Windows\Microsoft.NET\Framework64\v4.0.30319\Microsoft.Common.targets(609,5):错误:未为项目"A.csproj"设置OutputPath属性.请检查以确保您为此项目指定了Configuration和Platform的有效组合.Configuration ='Debug'Blatform ='x86'.您可能会看到此消息,因为您正在尝试构建没有解决方案文件的项目,并且已指定了此项目不存在的非默认配置或平台.[A.csproj] C:\ Windows\Microsoft.NET\Framework64\v4.0.30319\Microsoft.Common.targets(609,5):错误:未为项目"B.csproj"设置OutputPath属性.请检查以确保您为此项目指定了Configuration和Platform的有效组合.Configuration ='Debug'Blatform ='x86'.您可能会看到此消息,因为您正在尝试构建没有解决方案文件的项目,并且已指定了此项目不存在的非默认配置或平台.[B.csproj]

Answer 1

我找到了解决问题的方法.使用*.csproj文件中的Choose元素通过Visual Studio或MSBuild检测构建,并使用Reference(而不是ProjectReference)进行MSBuild.

<Choose>
  <When Condition="'$(BuildingInsideVisualStudio)' == 'true'">
    <ItemGroup>
      <ProjectReference Include="A.csproj">
        <Project>{AAAAAAAA-AAAA-AAAA-AAAA-AAAAAAAAAAAA}</Project>
        <Name>A</Name>
        <Private>True</Private>
      </ProjectReference>
      <ProjectReference Include="B.csproj">
        <Project>{BBBBBBBB-BBBB-BBBB-BBBB-BBBBBBBBBBBB}</Project>
        <Name>B</Name>
        <Private>True</Private>
      </ProjectReference>
    </ItemGroup>
  </When>
  <Otherwise>
    <ItemGroup>
      <Reference Include="A, Version=1.0.0.0, Culture=neutral, PublicKeyToken=xxxxxxxxxxxxxxxx, processorArchitecture=MSIL">
        <HintPath>A.dll</HintPath>
        <Private>True</Private>
      </Reference>
      <Reference Include="B, Version=1.0.0.0, Culture=neutral, PublicKeyToken=xxxxxxxxxxxxxxxx, processorArchitecture=MSIL">
        <HintPath>B.dll</HintPath>
        <Private>True</Private>
      </Reference>
    </ItemGroup>
  </Otherwise>
</Choose>