Ale*_*x R 6 python arrays json multidimensional-array
我在我脑海中,试图第一次解析JSON并处理多维数组.
{
"secret": "[Hidden]",
"minutes": 20,
"link": "http:\/\/www.1.com",
"bookmark_collection": {
"free_link": {
"name": "#free_link#",
"bookmarks": [
{
"name": "1",
"link": "http:\/\/www.1.com"
},
{
"name": "2",
"link": "http:\/\/2.dk"
},
{
"name": "3",
"link": "http:\/\/www.3.in"
}
]
},
"boarding_pass": {
"name": "Boarding Pass",
"bookmarks": [
{
"name": "1",
"link": "http:\/\/www.1.com\/"
},
{
"name": "2",
"link": "http:\/\/www.2.com\/"
},
{
"name": "3",
"link": "http:\/\/www.3.hk"
}
]
},
"sublinks": {
"name": "sublinks",
"link": [
"http:\/\/www.1.com",
"http:\/\/www.2.com",
"http:\/\/www.3.com"
]
}
}
}
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这分为3个部分,我的第一个维度上的静态数据(秘密,分钟,链接)我需要作为单独的字符串获取.
然后我需要一个没有固定名称的"书签集"字典,所以我需要它们的名称和每个书签的链接/名称.
然后是单独的子链接,它总是相同的,我需要单独的字典中的所有链接.
我正在阅读有关解析JSON的内容,但我找到的大部分内容都是一个放入1个字典的简单数组.有没有人有任何好的技巧来做到这一点?
小智 12
在解析JSON之后,最终会得到一个Python dict.因此,假设上面的JSON位于名为input_data的字符串中:
import json
# This converts from JSON to a python dict
parsed_input = json.loads(input_data)
# Now, all of your static variables are referenceable as keys:
secret = parsed_input['secret']
minutes = parsed_input['minutes']
link = parsed_input['link']
# Plus, you can get your bookmark collection as:
bookmark_collection = parsed_input['bookmark_collection']
# Print a list of names of the bookmark collections...
print bookmark_collection.keys() # Note this contains sublinks, so remove it if needed
# Get the name of the Boarding Pass bookmark:
print bookmark_collection['boarding_pass']['name']
# Print out a list of all bookmark links as:
# Boarding Pass
# * 1: http://www.1.com/
# * 2: http://www.2.com/
# ...
for bookmark_definition in bookmark_collection.values():
# Skip sublinks...
if bookmark_definition['name'] == 'sublinks':
continue
print bookmark_definition['name']
for bookmark in bookmark_definition['bookmarks']:
print " * %(name)s: %(link)s" % bookmark
# Get the sublink definition:
sublinks = parsed_input['bookmark_collection']['sublinks']
# .. and print them
print sublinks['name']
for link in sublinks['link']:
print ' *', link
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