以下代码将帮助您理解我的问题:
create table con ( content_id number);
create table mat ( material_id number, content_id number, resolution number, file_location varchar2(50));
create table con_groups (content_group_id number, content_id number);
insert into con values (99);
insert into mat values (1, 99, 7, 'C:\foo.jpg');
insert into mat values (2, 99, 2, '\\server\xyz.mov');
insert into mat values (3, 99, 5, '\\server2\xyz.wav');
insert into con values (100);
insert into mat values (4, 100, 5, 'C:\bar.png');
insert into mat values (5, 100, 3, '\\server\xyz.mov');
insert into mat values (6, 100, 7, '\\server2\xyz.wav');
insert into con_groups values (10, 99);
insert into con_groups values (10, 100);
commit;
SELECT m.material_id,
(SELECT file_location
FROM (SELECT file_location
FROM mat
WHERE mat.content_id = m.content_id
ORDER BY resolution DESC) special_mats_for_this_content
WHERE rownum = 1) special_mat_file_location
FROM mat m
WHERE m.material_id IN (select material_id
from mat
inner join con on con.content_id = mat.content_id
inner join con_groups on con_groups.content_id = con.content_id
where con_groups.content_group_id = 10);
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请将查询末尾的数字10视为参数.换句话说,这个值在这个例子中只是硬编码; 它会根据输入而改变.
我的问题是:为什么我会收到错误
"M"."CONTENT_ID": invalid identifier
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对于嵌套的相关子查询?有某种嵌套限制吗?需要为结果集中的每一行运行此子查询,因为结果将根据content_id进行更改,而content_id对于每一行可能会有所不同.我如何用Oracle实现这一目标?
并不是说我正在尝试启动SQL Server与Oracle讨论,但我来自SQL Server后台,我想指出以下等效查询在SQL Server上正常运行:
create table con ( content_id int);
create table mat ( material_id int, content_id int, resolution int, file_location varchar(50));
create table con_groups (content_group_id int, content_id int);
insert into con values (99);
insert into mat values (1, 99, 7, 'C:\foo.jpg');
insert into mat values (2, 99, 2, '\\server\xyz.mov');
insert into mat values (3, 99, 5, '\\server2\xyz.wav');
insert into con values (100);
insert into mat values (4, 100, 5, 'C:\bar.png');
insert into mat values (5, 100, 3, '\\server\xyz.mov');
insert into mat values (6, 100, 7, '\\server2\xyz.wav');
insert into con_groups values (10, 99);
insert into con_groups values (10, 100);
SELECT m.material_id,
(SELECT file_location
FROM (SELECT TOP 1 file_location
FROM mat
WHERE mat.content_id = m.content_id
ORDER BY resolution DESC) special_mats_for_this_content
) special_mat_file_location
FROM mat m
WHERE m.material_id IN (select material_id
from mat
inner join con on con.content_id = mat.content_id
inner join con_groups on con_groups.content_id = con.content_id
where con_groups.content_group_id = 10);
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能否帮助我理解为什么我可以在SQL Server中执行此操作但不能在Oracle 9i中执行此操作?如果存在嵌套限制,如何在Oracle中的单个选择查询中完成此操作而不使用循环和/或临时表?
最新版本的Oracle没有限制,但大多数旧版本的Oracle都具有1深度的嵌套限制.
这适用于所有版本:
SELECT (
SELECT *
FROM dual dn
WHERE dn.dummy = do.dummy
)
FROM dual do
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此查询在12c和18c中有效,但在10g和11g中不起作用.(但是,至少有一个10g版本允许此查询.并且有一个补丁可以在11g中启用此行为.)
SELECT (
SELECT *
FROM (
SELECT *
FROM dual dn
WHERE dn.dummy = do.dummy
)
WHERE rownum = 1
)
FROM dual do
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如果有必要,你可以使用窗口函数解决这个限制(你可以使用它SQL Server:)
SELECT *
FROM (
SELECT m.material_id, ROW_NUMBER() OVER (PARTITION BY content_id ORDER BY resolution DESC) AS rn
FROM mat m
WHERE m.material_id IN
(
SELECT con.content_id
FROM con_groups
JOIN con
ON con.content_id = con_groups.content_id
WHERE con_groups.content_group_id = 10
)
)
WHERE rn = 1
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