我可以使用URL作为imagecreatefromjpeg()的源而不启用fopen包装器吗？

Question

我知道可以使用imagecreatefromjpeg(),imagecreatefrompng()等将URL作为'filename'和fopen(),但由于安全问题,我无法启用包装器.有没有办法将URL传递给imagecreatefromX()而不启用它们？

我也尝试过使用cURL,这也给我带来了问题:

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,"http://www.../image31.jpg"); //Actually complete URL to image
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$data = curl_exec($ch);
curl_close($ch);

$image = imagecreatefromstring($data);
var_dump($image);

imagepng($image);
imagedestroy($image);

Answer 1

您可以使用cURL下载文件,然后将结果通过管道传输到imagecreatefromstring.

例:

    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, $imageurl); 
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); // good edit, thanks!
    curl_setopt($ch, CURLOPT_BINARYTRANSFER, 1); // also, this seems wise considering output is image.
    $data = curl_exec($ch);
    curl_close($ch);

    $image = imagecreatefromstring($data);