How*_*wie 9 sql oracle aggregate-functions oracle11g oracle11gr2
我正在使用Oracle 11g r2,我需要从多行连接字符串(VARCHAR2,300).我正在使用LISTAGG哪个工作很好,直到连接的字符串达到限制.那时我收到了一个ORA-01489: result of string concatenation is too long.
最后,我只想要串联字符串的前4000个字符.我如何到达并不重要.我会接受效率低下的解决方案.
这是我的查询:
SELECT LISTAGG(T.NAME, ' ') WITHIN GROUP (ORDER BY NULL)
FROM T
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您可以使用内置(但已弃用)STRAGG 函数
select sys.stragg(distinct name) from t
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(请注意,不同似乎是避免重复所必需的)
或定义您自己的聚合函数/类型:
CREATE OR REPLACE TYPE "STRING_AGG_TYPE" as object
(
total varchar2(4000),
static function ODCIAggregateInitialize(sctx IN OUT string_agg_type) return number,
member function ODCIAggregateIterate(self IN OUT string_agg_type,
value IN varchar2) return number,
member function ODCIAggregateTerminate(self IN string_agg_type,
returnValue OUT varchar2,
flags IN number) return number,
member function ODCIAggregateMerge(self IN OUT string_agg_type,
ctx2 IN string_agg_type) return number
);
CREATE OR REPLACE TYPE BODY "STRING_AGG_TYPE" is
static function ODCIAggregateInitialize(sctx IN OUT string_agg_type) return number is
begin
sctx := string_agg_type(null);
return ODCIConst.Success;
end;
member function ODCIAggregateIterate(self IN OUT string_agg_type,
value IN varchar2) return number is
begin
-- prevent buffer overflow for more than 4,000 characters
if nvl(length(self.total),
0) + nvl(length(value),
0) < 4000 then
self.total := self.total || ';' || value;
end if;
return ODCIConst.Success;
end;
member function ODCIAggregateTerminate(self IN string_agg_type,
returnValue OUT varchar2,
flags IN number) return number is
begin
returnValue := ltrim(self.total,
';');
return ODCIConst.Success;
end;
member function ODCIAggregateMerge(self IN OUT string_agg_type,
ctx2 IN string_agg_type) return number is
begin
self.total := self.total || ctx2.total;
return ODCIConst.Success;
end;
end;
CREATE OR REPLACE FUNCTION stragg(input varchar2 )
RETURN varchar2
PARALLEL_ENABLE AGGREGATE USING string_agg_type;
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并像这样使用它:
select STRAGG(name) from t
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我相信这种方法最初是由 Tom Kyte 提出的(至少,我是从那里得到的 - Asktom: StringAgg