Lor*_*v8r 3 sql sql-server-2008
我是SQL Server的新手,我还在学习交易的一些技巧,而另一个教我的人本周都没有工作,通常我会首先运行他的声明,然后运行它.
我要做的是删除此select语句中返回的所有内容:
SELECT * from LOCATIONS a Join CONTACTS b on a.location_ID = b.Location_ID
join CONTACTS_SOURCES c on b.contact_ID = c.Contact_ID where c.Source_ID = 10014918
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我需要删除此语句从CONTACTS表和LOCATIONS表中返回的内容.这样做的路线是最好的路线?
路线A:
delete from LOCATIONS a
Join CONTACTS b
on a.location_ID = b.Location_ID
join CONTACTS_SOURCES c
on b.contact_ID = c.Contact_ID where c.Source_ID = 10014918
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或路线B.
DELETE from LOCATIONS where (SELECT * from LOCATIONS a
Join CONTACTS b
on a.location_ID = b.Location_ID
join CONTACTS_SOURCES c
on b.contact_ID = c.Contact_ID where c.Source_ID = 10014918)
DELETE FROM CONTACTS where (SELECT * from LOCATIONS a
Join CONTACTS b
on a.location_ID = b.Location_ID
join CONTACTS_SOURCES c
on b.contact_ID = c.Contact_ID where c.Source_ID = 10014918)
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我感觉路线A.不会从LOCATIONS和CONTACTS表中删除.
您的感觉是正确的:DELETE查询(任何DML查询,实际上)只能影响单个表.路由B的问题是第二个查询不起作用,因为第一个查询删除了所有可能成为连接的候选行.
怎么样:
SELECT l.Location_ID, c.Contact_ID
INTO #x
FROM dbo.LOCATIONS AS l
INNER JOIN dbo.CONTACTS AS c
ON l.location_ID = c.Location_ID
INNER JOIN dbo.CONTACTS_SOURCES AS cs
ON c.contact_ID = cs.Contact_ID
WHERE cs.Source_ID = 10014918;
DELETE dbo.CONTACTS_SOURCES WHERE Contact_ID IN (SELECT Contact_ID FROM #x);
DELETE dbo.CONTACTS WHERE Contact_ID IN (SELECT Contact_ID FROM #x);
DELETE dbo.LOCATIONS WHERE Location_ID IN (SELECT Location_ID FROM #x);
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