如何删除C#4.0中指定的xmlnode的所有子节点？

Question

这是我的xml.

<Document>
<page no="1">
  <Paragraph no="1">
    <Line>line1</Line>
  </Paragraph>
  <Paragraph no="2">
    <Line>line2</Line>
  </Paragraph>
</page>
<page no="2">
  <Paragraph no="1">
    <Line>line1</Line>
  </Paragraph>
  <Paragraph no="2">
    <Line>line2</Line>
  </Paragraph>
</page>
</Document>

我的C#代码是

XmlDocument xd = new XmlDocument();
            xd.Load(@"H:\Sample-8-final.xml");
            XmlNodeList pnodelist = xd.GetElementsByTagName("page");
            XmlNodeList xdChildNodeList = xd.ChildNodes;

            for (int i = 0; i < pnodelist.Count; i++)
            {
                XmlNode pageNode = pnodelist[i];
                foreach (XmlNode xxNode in pageNode.ChildNodes)
                {
                    if (xxNode.Name.ToString().Trim().Equals("Paragraph"))
                    {
                        foreach (XmlNode yyNode in xxNode.ChildNodes)
                        {
                            yyNode.ParentNode.RemoveChild(yyNode);
                        }
                    }
                }
                xd.Save(@"H:\Sample-8-final_1.xml");

我的必需输出是

<Document>
<page no="1">
  <Paragraph no="1">
  </Paragraph>
  <Paragraph no="2">
  </Paragraph>
</page>
<page no="2">
  <Paragraph no="1">
  </Paragraph>
  <Paragraph no="2">
  </Paragraph>
</page>
</Document>

但我的代码产生了错误的结果如下:

<Document>
    <page no="1">
      <Paragraph no="1">
      </Paragraph>
      <Paragraph no="2">
        <Line>line2</Line>
      </Paragraph>
    </page>
    <page no="2">
      <Paragraph no="1">
      </Paragraph>
      <Paragraph no="2">
        <Line>line2</Line>
      </Paragraph>
    </page>
    </Document>

请指导我摆脱这个问题......

Answer 1

使用LINQ to XML删除Paragraph元素的所有后代:

XElement root = XElement.Load(@"H:\Sample-8-final_1.xml");
root.Descendants("Paragraph").Descendants().Remove();

注意:您需要放在using System.Xml.Linq;文件的顶部.