如何在python中初始化time()对象

Question

我正在尝试初始化这样的时间对象:

t = datetime.time(0,0,0)

但我收到这个错误:

descriptor 'time' requires a 'datetime.datetime' object but received a 'int'

我有这些东西进口了

import datetime
from datetime import datetime, date, time
import time

它们似乎有点多余,所以我想知道这是否是导致问题的原因

我也在使用strptime方法和combine方法

    earliest = datetime.combine(earliest, t)
    value = datetime.strptime(value, format)

Answer 1

您可以创建没有任何值的对象:

>>> import datetime
>>> datetime.time()
datetime.time(0, 0)

但是,您从模块导入了类 datetime,替换了模块本身:

>>> from datetime import datetime
>>> datetime.time
<method 'time' of 'datetime.datetime' objects>

这有不同的签名:

>>> datetime.time()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: descriptor 'time' of 'datetime.datetime' object needs an argument
>>> datetime.time(0)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: descriptor 'time' requires a 'datetime.datetime' object but received a 'int'

导入整个模块,或导入包含的类,但不要混合和匹配.依照:

import datetime
import time

如果你需要两个模块.

Answer 2

时间的构造函数是:

class datetime.time(hour[, minute[, second[, microsecond[, tzinfo]]]])

(来自http://docs.python.org/library/datetime.html#time-objects)

这对我有用:

In [1]: import datetime

In [2]: t = datetime.time(0, 0, 0)

In [3]: print t
00:00:00

Answer 3

事实上,你是import一个冲突datetime的人datetime.你可能意味着time,除了你也是 import冲突的time.那怎么样:

import datetime as dt

和

t = dt.time(0, 0, 0)