沿任意轴切片

Joh*_*åde 5 python indexing numpy

我有一个numpy的阵列A,使得

A.shape[axis] = n+1.
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现在我想建立两片BCA通过选择指数0, .., n-11, ..., n沿轴分别axis.从而

B.shape[axis] = C.shape[axis] = n
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BC具有的尺寸相同A沿其它轴.必须没有数据复制.

Nic*_*bey 9

# exemple data
A = np.random.rand(2, 3, 4, 5)
axis = 2
n = A.ndim
# building n-dimensional slice
s = [slice(None), ] * n
s[axis] = slice(0, n - 1)
B = A[s]
s[axis] = slice(1, n)
C = A[s]
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单行:

B = A[[slice(None) if i != axis else slice(0, n-1) for i in xrange(n)]]
C = A[[slice(None) if i != axis else slice(1, n) for i in xrange(n)]]
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